Separation of variables on 2nd order ode

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SUMMARY

The discussion centers on the application of separation of variables in second-order ordinary differential equations (ODEs), specifically addressing the equation y'' = x. Participants clarify that while y' = x can be solved by separating variables, y'' = 0 can also be manipulated by multiplying both sides by dx, leading to y''dx = 0dx. The key takeaway is understanding the legal manipulation of derivatives and the implications of integrating second derivatives, emphasizing that if the second derivative of a function is zero, the first derivative is a constant.

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  • Understanding of ordinary differential equations (ODEs)
  • Familiarity with calculus concepts, particularly derivatives and integrals
  • Knowledge of separation of variables technique
  • Basic algebraic manipulation skills
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  • Explore the implications of integrating second-order derivatives
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Students and professionals in mathematics, particularly those studying differential equations, as well as educators seeking to clarify concepts related to ODEs and integration techniques.

koab1mjr
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Hi all

Quick one, if one had an equation y' = x on could simply separate the variables and integrate. Now it the equation y'' = x you would use separation of variables what drives this?

Also

y'' =0. Is the same as. y''dx =0 dx
Why is this legal?Thanks in advance
 
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Well, you can always multiply both sides of an equation by the same thing! So, yes, y''= 0 is the same as y''dx= 0dx= 0. And you can now integrate both sides of the equation, with respect to x, to get y'(x)= C where C is a constant of integration. But you did not really need to do that. You know, I hope, that if the derivative of a function is 0, then the function is a constant: if the second derivative of y is 0, the first derivative is a constant.
 
Ok re read what I wrote and my main question is not clear

Why is

D^2y/Dx^2 = 0 not the same as d^2y =0 dx^2

On one side u get a line on the other u get something else what is the rigorous explanation
 
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