Convergence of Series Involving Logarithms and Reciprocals

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SUMMARY

The series ##\sum_{n=1}^{\infty}\frac{\log (1+1/n)}{n}## converges, as established through the inequality ##\log (1+1/n) < 1/n##. This approach simplifies the proof of convergence by leveraging known properties of logarithmic functions. The discussion highlights the importance of understanding the definition and properties of the logarithm in various mathematical contexts, including limits and series.

PREREQUISITES
  • Understanding of logarithmic functions and their properties
  • Familiarity with series convergence tests
  • Basic knowledge of inequalities in mathematical analysis
  • Experience with limits and their applications in calculus
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  • Study the proof of convergence for series using the Comparison Test
  • Explore the properties of logarithmic functions in calculus
  • Learn about the Integral Test for series convergence
  • Investigate the relationship between logarithms and exponential functions
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Mathematics students, educators, and anyone interested in advanced calculus and series convergence, particularly those focusing on logarithmic functions and their applications in analysis.

Mr Davis 97
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Homework Statement


Show that ##\sum_{n=1}^{\infty}\frac{\log (1+1/n)}{n}## converges.

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The Attempt at a Solution


If I take for granted the inequality ##\log (1+1/n) < 1/n##, I can easily show that this converges. My problem is is that I am not seeing how to prove convergence another way...
 
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Not sure why you want to do it another way. But in any case, the first question is: What is ##\log(.)##? Is it a limit, a series, the solution of a functional equation, an isomorphism, an integral, the solution of a differential equation, or just the solution to ##e^x=c\,?## So any approach depends on what you have. Which is it? And it might happen, that the first step will be to deduce some appropriate boundary and you'll end up at what you wanted to avoid.
 

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