Series solutions near a regular singular point

  • Context: Graduate 
  • Thread starter Thread starter phrankle
  • Start date Start date
  • Tags Tags
    Point Regular Series
Click For Summary
SUMMARY

The discussion focuses on the application of the Frobenius method for solving series solutions near a regular singular point. It clarifies that the indices of summation derivatives do not shift because maintaining the original index ensures that the coefficients \( A_n \) align correctly with the respective powers of \( x \). The participant emphasizes that changing the index would complicate the expression and increase the risk of errors. This understanding is crucial for correctly applying the Frobenius method in differential equations.

PREREQUISITES
  • Frobenius method for solving differential equations
  • Understanding of power series expansions
  • Basic calculus, specifically differentiation of series
  • Familiarity with regular singular points in differential equations
NEXT STEPS
  • Study the Frobenius method in detail, focusing on its application to regular singular points
  • Learn about power series and their convergence properties
  • Explore differentiation techniques for series, including index manipulation
  • Investigate examples of differential equations that utilize the Frobenius method
USEFUL FOR

Mathematics students, educators, and researchers interested in differential equations, particularly those focusing on series solutions and the Frobenius method.

phrankle
Messages
6
Reaction score
0
For solving a series solution near a regular singular point with the Frobenius method, why is it that the indices of summation derivatives aren't shifted?

For example, in my textbook and lecture notes

y = [tex]\sum[/tex]A[tex]_{}n[/tex]x[tex]^{}n+r[/tex] from n=0 to infinity

y' = [tex]\sum[/tex](n+r)A[tex]_{}n[/tex]x[tex]^{}n+r-1[/tex] from n=0 to infinity

y'' = [tex]\sum[/tex](n+r)(n+r-1)A[tex]_{}n[/tex]x[tex]^{}n+r-2[/tex] from n=0 to infinity


But shouldn't the index for y' be from n=1 to infinity because it shifts up when you take the derivative of a summation? Shouldn't the index for y'' be from n=2 to infinity?

Thanks.
 
Physics news on Phys.org
Welcome to PF!

Hi phrankle! Welcome to PF! :smile:

No, because then your An wouldn't match your x^(n+r-1), would it?

Of course, you could change it to ∑A(n+1)x^(n+r), and do it from n = -1 to ∞ …

but that would be unnecessarily complicated, and you could easily make a mistake … :frown:
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 0 ·
Replies
0
Views
4K
  • · Replies 2 ·
Replies
2
Views
6K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K