Series with binomial coefficients

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Discussion Overview

The discussion revolves around a mathematical identity involving binomial coefficients and sums, as presented in a Mathematica code snippet. Participants are exploring the analytical reasoning behind the identity, which Mathematica confirms as true but remains unclear to the original poster.

Discussion Character

  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • The original poster presents an equation in Mathematica that is confirmed as an identity but seeks an analytical explanation for this result.
  • Some participants suggest translating the equation into LaTeX for clarity.
  • A participant attempts to provide a LaTeX representation of the equation, although it is noted that the formatting is not correct.
  • Another participant comments on the complexity of the expression and suggests focusing on the terms to the right of the binomial coefficients for potential equality.

Areas of Agreement / Disagreement

The discussion does not reach a consensus on the analytical reasoning behind the identity, and participants express varying levels of clarity regarding the mathematical expressions involved.

Contextual Notes

There are limitations in the clarity of the mathematical expressions due to formatting issues, and the original poster's parameters for the variables are not fully explored in the discussion.

ydydry
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Hi all, I have an apparently simple equation. I copy here its Mathematica code:

Sum[(p/(1 - p))^s*(q/(1 - q))^s*Binomial[n, s]*(Binomial[m - 1, s]*(p*q*(m + n) + (2*m - 1)*(-p - q + 1))), {s, 0, n}] == Sum[(p/(1 - p))^s*(q/(1 - q))^s*Binomial[n, s]*((-(-p - q + 1))*Binomial[m - 2, s] + m*p*q*Binomial[m, s] + m*(-p - q + 1)*(Binomial[m - 2, s] + Binomial[m, s])), {s, 0, n}]

Mathematica's FullSimplify command immediately tells me that it is an identity, giving me "True" as output, but I fail to see the analytical reason.

All parameters are weakly positive and reals, although I do not need to assume anything for Mathematica to tell me that it is indeed an identity.

Thanks a lot!
 
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Try translating the equation into latex form.
 
\overset{n}{\underset{s=0}{\sum }}\left( \frac{pq}{(1-p)(1-q)}\right)
^{s}\left( \begin{array}{c}n \\
s%
\end{array}%
\right) \left[ \left( \begin{array}{c}m-1 \\
s%
\end{array}%
\right) (pq(m+n)+(2m-1)(1-p-q))\right] =\overset{n}{\underset{s=0}{\sum }}%
\left( \frac{pq}{(1-p)(1-q)}\right) ^{s}\left( \begin{array}{c}n \\
s%
\end{array}%
\right) \left[ (m-1)\left( \begin{array}{c}m-2 \\
s%
\end{array}%
\right) (1-p-q)+\left( \begin{array}{c}m \\
s%
\end{array}%
\right) mpq+\left( \begin{array}{c}m \\
s%
\end{array}%
\right) m(1-p-q))\right]
 
I apologize for the last attempt to write the code in Latex. I am not familiar with the software, and I clearly failed. I enclose a picture of the expression, which should be more readable than the non-sense above code
 

Attachments

  • Sin título.png
    Sin título.png
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It looks messy enough. Try looking at the expression to the right of nCs on both sides and see if they are equal.
 

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