Sets: A,B,C - Intersection & Difference

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Fermat1
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Am I right in thinking that if we have 3 sets A,B,C, then with A intersect B represented as AB, we have:

A(B\C)=(AB)\C=B(A\C)?
 
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Yes. This follows from the definition of set minus.
 
All three sets equal $A\cap B\cap\bar{C}$ where $\bar{C}$ is the complement of $C$.