Shaft Sizing: Calculating σmax from 1045 UTS/YTS

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The discussion focuses on calculating the maximum stress (σmax) for shaft sizing using the formula D = 1.72 (Tmax/σmax)^1/3. The material in question is 1045 steel, with a UTS of 84,800 psi and a YTS of 74,300 psi. Participants suggest using the yield strength (YTS) as a rough estimate for σmax, emphasizing that this approach is valid for ductile materials under static, pure shear conditions.

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Attempting to use the formula:
D = 1.72 (Tmax/σmax)^1/3

In my case I do not know σmax or at least how to calculate it from material properties.
Material is 1045
UTS 84800
YTS 74300
Tmax = 591.55 in-lbs

D = 1.72 (Tmax/σmax)^1/3

Any help would be appreciated.

Regards
 
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As a very rough pass, you can use your yield strength as [tex]\sigma_{max}[/tex]. Your equation is essentially assuming a set relationship for ductile materials and the relationship between shear stresses and normal stresses. This is for static, pure shear only.
 

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