Calculating Frequency in SHM with Amplitude, Velocity, and Mass

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SUMMARY

The discussion focuses on calculating the frequency of simple harmonic motion (SHM) using amplitude, velocity, and mass. The user provided example values: velocity (v) of 5 m/s, amplitude (A) of 10 m, and mass (m) of 3 kg. Two methods were explored: one using the derivative of the SHM equation and the other applying Hooke's Law (F = -K(x - xo)). The calculated frequencies were approximately 0.0795 Hz and 0.1576 Hz, with the user expressing confusion about the correct approach.

PREREQUISITES
  • Understanding of simple harmonic motion (SHM) equations
  • Knowledge of Hooke's Law (F = -K(x - xo))
  • Familiarity with angular frequency (w = 2 * PI * f)
  • Basic calculus for derivatives in motion equations
NEXT STEPS
  • Study the derivation of frequency in simple harmonic motion using SHM equations
  • Learn about the relationship between spring constant (K) and frequency (f) in SHM
  • Explore the implications of amplitude and mass on frequency calculations
  • Investigate the effects of damping on simple harmonic motion
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and oscillations, as well as educators seeking to clarify concepts related to simple harmonic motion and frequency calculations.

izzyfish
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I feel like an idiot for not being able to answer this question, it seemed so simple yet so complicated in my head.

Homework Statement


Have to find frequency, given the amplitude, velocity, and mass.
I don't have numbers as it was off an exam I just took. Guessing it was v=5 m/s; A=10m; and m=3kg.


Homework Equations


I was thinking of taking the derivative of the SHM eq x(t) = Asin(wt) but then I wasn't sure if I could calculate the spring constant with F = -K(xo - xf).


The Attempt at a Solution


My attempt was guessing, but if we threw in numbers, A=10m, v=5m/s, m=3kg...
x(t) = A * sin(wt)
w = 2 * PI * f
x(t) = A * sin(2 * PI * f * t)
v(t) = 2 * PI * f * A * cos(2 * PI * f * t)
t = 0
5 = 2 * PI * f * 10 * cos(2 * PI * f * 0)
5 = 2 * PI * f * 10 * 1
5 = 20 * PI * f
5 / (20 * PI) = f
f = 0.0795Hz

or..

F=-K(x-xo)
F = 3*9.8 = 29.4
x = 10
xo = 0
K = 2.94 N/m
f = (1 /( 2 * PI )) * sqrt( k / m)
f = 0.159 * sqrt (2.94 / 3 )
f = 0.1576 Hz

Would love to know the correct way to do this, as I'm confused..
 
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Using F=kx would depend on how the spring is orientated. But I would use your first method.
 

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