Shortcuts for Solving Brutal Limit Problems

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Homework Statement

Limit x tends to zero, (sin(tan(x))-tan(sin(x)))/x^7

Homework Equations


The Attempt at a Solution



I have tried to derive a maclaurin expansion for sin(tan(x)) and tan(sin(x)).
But it was too lengthy to be attempted in an examination.
Another method is to use l'hospital but this method is also incredibly lengthy.

Is there a shorter method to attack this problem?
 
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lanedance said:
expanding each to O(x^8) should be more than enough, as those and any higher terms will tend to zero in the limit

Yeah, but calculating derivatives of sin(tan(x)) and tan(sin(x)) for taylor series, and keeping track of everything is a very long process.

I was wondering if an easier and shorter method is avaliable.
 
[tex]\sin\left(\tan\left(x\right)\right) = -\frac{1}{5040} \, tan(x)^{7} + \frac{1}{120} \, tan(x)^{5} - \frac{1}{6} \, tan(x)^{3} + tan(x)[/tex]

and

[tex]\tan\left(\sin\left(x\right)\right) = \frac{17}{315} \, sin(x)^{7} + \frac{2}{15} \, sin(x)^{5} + \frac{1}{3} \, sin(x)^{3} +<br /> sin(x)[/tex]
(x^8 is zero for both functions). Then ,
[tex]\frac{\sin\left(\tan\left(x\right)\right) -<br /> \tan\left(\sin\left(x\right)\right)}{x^{7}} =<br /> <br /> -\frac{272 \, \sin\left(x\right)^{7} + 672 \, \sin\left(x\right)^{5} +<br /> 1680 \, \sin\left(x\right)^{3} + \tan\left(x\right)^{7} - 42 \,<br /> \tan\left(x\right)^{5} + 840 \, \tan\left(x\right)^{3} + 5040 \,<br /> \sin\left(x\right) - 5040 \, \tan\left(x\right)}{5040 \, x^{7}}[/tex]

and then how do I proceed?
 
Last edited:
now substitute in the taylor expansions of sin & cos

it will seem messy at first, but as you only need keep terms up to O(x^7) you can throw away a lot

[tex] tan(x)^{7} = (\frac{17}{315}x^7 + \frac{2}{15}x^5 \ + \frac{1}{3} x^3 + x)^7 = x^7 + O(x^8)<br /> [/tex]