Shortest distance between two cars

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SUMMARY

The shortest distance between two cars approaching the origin on perpendicular roads occurs at approximately 31.7 seconds. The first car, starting 250 meters away and traveling at 6 m/s, and the second car, starting 350 meters away and traveling at 12 m/s, reach their minimum separation of 67.1 meters at this time. The calculation involves determining the distance function A and finding its minimum by setting the derivative dA/dt to zero.

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Homework Statement



Two straight roads, which are perpendicular to each other, cross at point O.

Suppose a car is at distance 250m from the origin on one road, and another car is at distance 350m from the origin on another road.

Both cars are approaching towards the origin.

The first car has a constant velocity of 6m/s and the second car has constant velocity of 12m/s.

When does the distance between the two cars become shortest? And what's that shortest distance?

Homework Equations



The Attempt at a Solution



Lets suppose at time t the cars' distance becomes shortest.
So at that time the first car's position will be (0, 250 - 6t) and the second car's position would be (350 - 12t, 0)

So distance between them is √{(350 - 12t)2 + (250 - 6t)2}

Next suppose A = (350 - 12t)2 + (250 - 6t)2
For minimum dA/dt = 0 from here I get t

Is my approach ok? (I am not much expert in calculus.)
 
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Looks reasonable. Solve for t in dA/dt = 0 and insert into your expression for the distance.
 
Thanks.

A = 180t2 - 11400t + 185000
dA/dt = 360t - 11400 = 0 gives t = 31.7
And the minimum distance is √{(350 - 12t)2 + (250 - 6t)2} = 67.1
 

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