Shortest distance between two cars

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Homework Help Overview

The problem involves two cars approaching the origin on perpendicular roads, with specified distances and velocities. The goal is to determine when the distance between the two cars is shortest and what that distance is.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to express the positions of the cars over time and formulate the distance between them as a function of time. Some participants question the validity of the approach and suggest solving for critical points to find the minimum distance.

Discussion Status

Participants have engaged in calculations related to the distance function and have provided feedback on the original poster's approach. A specific value for time has been calculated, and a minimum distance has been reported, though there is no explicit consensus on the correctness of the results.

Contextual Notes

The original poster expresses uncertainty regarding their calculus skills, which may influence the discussion dynamics and the level of guidance provided.

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Homework Statement



Two straight roads, which are perpendicular to each other, cross at point O.

Suppose a car is at distance 250m from the origin on one road, and another car is at distance 350m from the origin on another road.

Both cars are approaching towards the origin.

The first car has a constant velocity of 6m/s and the second car has constant velocity of 12m/s.

When does the distance between the two cars become shortest? And what's that shortest distance?

Homework Equations



The Attempt at a Solution



Lets suppose at time t the cars' distance becomes shortest.
So at that time the first car's position will be (0, 250 - 6t) and the second car's position would be (350 - 12t, 0)

So distance between them is √{(350 - 12t)2 + (250 - 6t)2}

Next suppose A = (350 - 12t)2 + (250 - 6t)2
For minimum dA/dt = 0 from here I get t

Is my approach ok? (I am not much expert in calculus.)
 
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Looks reasonable. Solve for t in dA/dt = 0 and insert into your expression for the distance.
 
Thanks.

A = 180t2 - 11400t + 185000
dA/dt = 360t - 11400 = 0 gives t = 31.7
And the minimum distance is √{(350 - 12t)2 + (250 - 6t)2} = 67.1
 

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