Show that a nonlinear transformation preseves velocity

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SUMMARY

This discussion focuses on demonstrating that a nonlinear transformation preserves the uniform velocity of a particle moving in a frame \( S \) when transformed to frame \( S' \). The transformation is defined as \( x'^\mu=\dfrac{A_\nu^\mu x^\nu + b^\mu}{c_\nu x^\nu + d} \), where \( A_\nu^\mu, b^\mu, c_\nu, d \) are constants. The key conclusion is that to show uniform velocity, one must prove that if the acceleration \( \frac{d^2 x^i}{dt^2} = 0 \) in frame \( S \), then it follows that \( \frac{d^2 x'^i}{dt'^2} = 0 \) in frame \( S' \). This involves working with differentials and applying the chain rule to compute the necessary expressions.

PREREQUISITES
  • Understanding of nonlinear transformations in physics
  • Familiarity with the concept of uniform velocity and acceleration
  • Knowledge of differential calculus and the chain rule
  • Basic understanding of Lorentz transformations and their implications
NEXT STEPS
  • Study the properties of fractional linear transformations and their role in preserving inertial motion
  • Learn how to apply the chain rule in the context of transformations
  • Investigate the relationship between velocity and acceleration in different reference frames
  • Explore the implications of nonlinear transformations in relativistic physics
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This discussion is beneficial for physics students, particularly those studying classical mechanics and special relativity, as well as researchers interested in the mathematical foundations of transformations in physics.

SevenHells
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Homework Statement


I have a particle moving with uniform velocity in a frame ##S##, with coordinates $$ x^\mu , \mu=0,1,2,3. $$
I need to show that the particle also has uniform velocity in a frame ## S' ##, given by
$$x'^\mu=\dfrac{A_\nu^\mu x^\nu + b^\mu}{c_\nu x^\nu + d}, $$
with ## A_\nu^\mu,b^\mu,c_\nu x^\nu,d ## constant.

Homework Equations


I don't think these are very relevant because they're not the transformations for the question but
$$\Delta x = \gamma(\Delta x' + v\Delta t')$$
$$\Delta t = \gamma(\Delta t' + v\Delta x'/c^2)$$
$$\Delta x' = \gamma(\Delta x - v\Delta t)$$
$$\Delta t' = \gamma(\Delta t - v\Delta x/c^2)$$

The Attempt at a Solution


I wrote the ## S' ## coordinates out and using ## x'^0=t'##,##x'^1=x'##,##x'^2=y'##,##x'^3=z' ##, try to calculate the velocities but I don't think it's right. I'm not sure how to show a transformation preserves the particle velocity. Could anyone point me how to show this for the Lorentz transformations, and then I could try to do it for my transformations?
 
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Oh, and for inline math we use ## \#\# ## to start and end, not ##$##
 
BvU said:
Oh, and for inline math we use ## \#\# ## to start and end, not ##$##
I've fixed that now, thanks. Did you have something typed before "Oh,"?
 
Ummm, no ... :frown:
 
SevenHells said:
I have a particle moving with uniform velocity in a frame ##S##, with coordinates $$ x^\mu , \mu=0,1,2,3. $$
I need to show that the particle also has uniform velocity in a frame ## S' ##, given by
$$x'^\mu=\dfrac{A_\nu^\mu x^\nu + b^\mu}{c_\nu x^\nu + d}, $$
with ## A_\nu^\mu,b^\mu,c_\nu x^\nu,d ## constant.
"Uniform velocity" means zero acceleration. So you must show that if $$\frac{dv^i}{dt} \equiv \frac{d^2 x^i}{dt^2} = 0$$then
$$\frac{dv'^i}{dt'} \equiv\frac{d^2 x'^i}{dt'^2} = 0$$ (where ##i=1,2,3##).

BTW, what is the context of this problem? It's actually a classic -- the fractional linear transformations are known to be the most general transformations which preserve inertial motion. :-)

Not sure how much of a hint I should give you, so I'll start with this:

Work with the differentials, i.e., find ##dx^i## and ##dt## separately, then take their quotient to find an expression for ##v##. Take differential ##dv## similarly, and take its quotient with ##dt## to find the acceleration.

Further hints: use the chain rule to compute the various differentials.
 

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