Show that any composite three-digit number must have a prime factor

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Homework Help Overview

The discussion revolves around the proof that any composite three-digit number must have a prime factor less than or equal to 31. Participants are exploring the implications of prime factorization in the context of composite numbers and their properties.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss a proof by contradiction and the implications of prime factors in relation to the square root of composite numbers. There is mention of a lemma regarding the largest prime factor of a composite number.

Discussion Status

The discussion is active, with participants providing feedback on the proof's structure and suggesting the inclusion of a lemma to strengthen the argument. There is an ongoing exploration of the proof's clarity and directness.

Contextual Notes

Some participants note the importance of the lemma regarding prime factors and question the placement of this lemma within the proof. There is also a discussion about the correct formulation of the negation of the original proposition.

Math100
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Homework Statement
Show that any composite three-digit number must have a prime factor less than or equal to ## 31 ##.
Relevant Equations
None.
Proof:

Suppose for the sake of contradiction that any composite three-digit number
must have a prime factor not less than or equal to ## 31 ##.
Let ## n ## be any composite three-digit number such that ## n=ab ## for
some ## a,b\in\mathbb{Z} ## where ## a,b>1 ##.
Note that the smallest prime factor greater than ## 31 ## is ## 37 ##.
Then we have ## a,b\geq 37 ##.
Thus ## n=ab\geq (37)^2=1369 ##.
This is a contradiction because ## 1369 ## is not a composite three-digit number.
Therefore, any composite three-digit number must have a prime factor less than or equal to ## 31 ##.
 
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Math100 said:
Then we have ## a,b\geq 37 ##.
Better would be "##max(a, b) \ge 37##"
The largest three-digit number is 999. ##\sqrt{999} \approx 31.61##, so if ##n = ab## is a three-digit composite number that is smaller than 999, the larger of its prime factors must be less than or equal to 31.
 
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I omitted the fact that for any composite, positive integer N, the largest prime factor must be less than or equal to ##\sqrt N##. You might want to prove that as a lemma that supports the problem you're working on.
 
Mark44 said:
I omitted the fact that for any composite, positive integer N, the largest prime factor must be less than or equal to ##\sqrt N##. You might want to prove that as a lemma that supports the problem you're working on.
Do I need to change my proof to another method? Or is proof by contradiction okay?
 
I don't see anything wrong with your proof, except that it less direct than it could be.
 
Mark44 said:
I don't see anything wrong with your proof, except that it less direct than it could be.
About where should I insert the lemma which you've mentioned?
 
Math100 said:
About where should I insert the lemma which you've mentioned?
A lemma should come before a proof that refers to it.
 
Lemma: For any composite positive integer ## N ##,
the largest prime factor must be less than or equal to ## \sqrt{N} ##.

Proof:

Note that the largest composite three-digit number is ## 999 ##.
Thus ## \sqrt{N}=\sqrt{999}\approx 31.61 ##.
Therefore, any composite three-digit number must have a prime factor
less than or equal to ## 31 ##.
 
But you should provide a proof of the lemma...
 
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Math100 said:
Homework Statement:: Show that any composite three-digit number must have a prime factor less than or equal to ## 31 ##.
Relevant Equations:: None.

Proof:

Suppose for the sake of contradiction that any composite three-digit number
must have a prime factor not less than or equal to ## 31 ##.
This is not the negation of the original proposition. The negation should be:

There exists a composite three-digit number with no primes factors less than or equal to 31.
 
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