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If angles A, B, and C are the angles of a triangle such that sin(A+B)=1/sin(C) and cos(A+B)=cos(C), then show that the triangle is a right triangle.
The discussion focuses on proving that a triangle is a right triangle given the equations sin(A+B) = 1/sin(C) and cos(A+B) = cos(C). By manipulating these equations, one can express A+B in terms of C and subsequently derive the values of angles A and B. The use of compound angle formulas is essential in this proof, leading to the conclusion that if these conditions hold, angle C must be 90 degrees, confirming the triangle's right-angle status.
PREREQUISITESStudents studying geometry, mathematics educators, and anyone interested in understanding trigonometric proofs related to triangle properties.