Sierpinski carpet - Moment of inertia

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The discussion centers on calculating the moment of inertia (MoI) for a Sierpinski carpet, which is known to have no area and thus no MoI in typical scenarios. The original poster seeks guidance on calculating MoI with a mass and length specified, particularly focusing on the z-axis. Participants suggest using the perpendicular axis theorem, which states that the MoI about the z-axis can be found by adding the MoI about the x and y axes. The conversation highlights the complexity of integrating the MoI due to the fractal nature of the Sierpinski carpet. Ultimately, the original poster successfully calculates the MoI using the theorem.
zl64c
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Hi, its my first post here, so i say HI :D
hm, i have a little problem with moment of interia. I know, that sierpinski carpet has no area and that's why with normal situation it also has not moment of interia (MoI). but now, i have special situation: mass - m, and length a. O and O' is perpendicular to the plan. i think is simple integral but maybe I am wrong? waiting for any ideas or any integrals to calc( love it ) :D:D

greetings form Poland
 
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Welcome to the forum!

I'm sorry to say that I don't understand your question. What exactly are you trying to compute?
 
Well what I am seeing is that it is basically a large square with squares in it cut out. So you can find the moment of inertia of the entire large square and then subtract the moments of inertia of the smaller squares (which may be a bit tedious as it looks)
 
rock.freak667 said:
Well what I am seeing is that it is basically a large square with squares in it cut out. So you can find the moment of inertia of the entire large square and then subtract the moments of inertia of the smaller squares (which may be a bit tedious as it looks)

yes, that's true. But i know how to calc MoI only Jx and Jy and here i have axis z. that's a problem.
 
zl64c said:
yes, that's true. But i know how to calc MoI only Jx and Jy and here i have axis z. that's a problem.

By the perpendicular axis theorem, Iz=Ix+Iy
 
i just calced it. thanks
 

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