Sig Figs in Chemistry: Calculate Mass of O2 from Gasoline

  • Thread starter Thread starter ilii
  • Start date Start date
  • Tags Tags
    Chemistry
Click For Summary
SUMMARY

The discussion focuses on calculating the mass of oxygen required for the complete combustion of 500.0g of octane (C8H18). The key steps include determining the moles of octane, calculating the moles of oxygen needed, and finally converting that to grams. It is established that all calculations should maintain four significant figures, as dictated by the initial value of 500.0g, ensuring precision throughout the multi-step process.

PREREQUISITES
  • Understanding of stoichiometry in chemical reactions
  • Knowledge of significant figures and their application in calculations
  • Familiarity with molar mass calculations
  • Basic principles of combustion reactions
NEXT STEPS
  • Study the concept of significant figures in detail
  • Learn how to balance combustion reactions involving hydrocarbons
  • Explore stoichiometric calculations for multi-step chemical reactions
  • Investigate the impact of precision in scientific measurements
USEFUL FOR

Chemistry students, educators, and anyone involved in chemical calculations or laboratory work who seeks to understand the importance of significant figures in quantitative analysis.

ilii
Messages
39
Reaction score
1

Homework Statement


Calculate what mass of oxygen is required to completely combust 500.0g of gasoline. Assume that the gasoline contains only octane.[/B]

Homework Equations



My problem is... I don't know WHEN to apply sig figs. If this is a multi-step problem (i to iv in this case), do I apply sig figs starting in i)? if I do, then all of my future answers will be influenced by using sig figs early on. When I get to iv) I don't know if all my digits are OK or if they're all way off. Can someone please clean the sig figs up a bit and tell me when I need to apply them? thank you!

The Attempt at a Solution


i) 2C(8)H(18) +25O(2) = 16CO(2) +18H(2)O

ii) 500.0g/114.22852 = 4.377 mol of C(8)H18)

iii) z=4.377 *25/2
z=54.71488206 mol
z=55 mol of O(2)

iv) m(O(2))=55mol*31.9988g/mol
m(O(2))=1759.934 g[/B]
m(O(2))=1760 g
 
Physics news on Phys.org
Do all calculations using full precision. Just the numbers you report should be rounded down.

As the initial value has 4 sigfigs, all your results should be reported to 4 sigfigs as well (hence 54.71 moles of oxygen, and not 55 moles).
 
ok, so you're saying that the initial 500.0 stems down through the entire series of steps to the question and 4 sig figs will always be required?
 
Last edited:
As it is the only number here - yes.

(That is - there are other numbers, like molar masses, but we typically know them with much higher accuracy).
 
ok thank you very helpful!
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 14 ·
Replies
14
Views
12K
Replies
1
Views
3K
  • · Replies 8 ·
Replies
8
Views
5K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 9 ·
Replies
9
Views
16K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
3
Views
9K
  • · Replies 3 ·
Replies
3
Views
3K