Significance of commutation of operators? position and momentum

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Discussion Overview

The discussion revolves around the significance of the commutation of operators, specifically focusing on the position and momentum operators in quantum mechanics. Participants explore the implications of commutation on the measurement of observables and the mathematical demonstration of whether these operators commute.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant inquires about the significance of the commutation of operators and seeks to understand how to demonstrate that the position and momentum operators do not commute.
  • Another participant explains that if operators commute, simultaneous measurements of the corresponding observables can be made with arbitrary accuracy, suggesting a relationship between commutation and measurement precision.
  • A participant mentions having done some calculations related to the topic, indicating ongoing exploration of the mathematical aspects.
  • A link to a previous discussion is provided for additional context or reference.

Areas of Agreement / Disagreement

No consensus is reached among participants regarding the significance or implications of the commutation of operators, and multiple viewpoints are presented without resolution.

Contextual Notes

The discussion does not clarify specific mathematical steps or definitions related to the concept of commuting operators, leaving some assumptions and dependencies unaddressed.

solas99
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significance of commutation of operators?

how do u show that the position and momentum operators do not commute?
 
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If the operators commute, and the operators correspond to observables, then it is possible to make simultaneous measurements of the observables to arbitrary accuracy.

You show that two operators do or do not commute by applying the definition of commuting and doing the math. So start from the definition.
 
ive done some working out..
 

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