Significant Figures: Cylinder Volume Calculation

Click For Summary

Homework Help Overview

The problem involves calculating the volume of a cylinder given its length and radius, with a focus on applying the rules of significant figures in the calculation.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the appropriate use of significant figures in intermediate calculations and the final result. There is debate over whether to round intermediate results or maintain full precision during calculations.

Discussion Status

The discussion is ongoing, with participants providing differing opinions on the treatment of significant figures. Some suggest that intermediate results should be rounded, while others advocate for using full precision until the final result is displayed.

Contextual Notes

There is a mention of using 22/7 for pi, which some participants question as a method for calculation. The original poster's final answer is also noted to differ from a suggested correct answer, indicating potential confusion or misinterpretation of significant figures.

zorro
Messages
1,378
Reaction score
0

Homework Statement



The length of a cylinder is 1.2 x 10^-2 m and its radius is 2.12 x 10^-2 m. What is its volume according to significicant figures?

Homework Equations





The Attempt at a Solution



V=(pi)r^2 l
r^2 = 4.49 x 10^-4 (as radius has 3 significant digits)
V= 22/7 x 4.49 x 10^-4 x 1.2 x 10^-2
V= 22/7 x 5.4 x 10^-6 [4.49 x 10^-4 x 1.2 x 10^-2 = 5.388 x 10^-6 = 5.4 x 10^-6 as least no. of significant digits is 2 here)
so V=1.7 x 10^-5

Answer is 16.9 x 10^-6
 
Physics news on Phys.org
1.7x10-5 m3 looks correct to me. But you should not use 22/7 for pi nor round down intermediate results.

--
 
Intermediate results have to be rounded off in order to satisfy the rules of significant figures.
 
No. You should round them down only if you are displaying them, but you do the calculations using full accuracy.

--
 
you mean to say that
5.388 x 10^-6 = 5.4 x 10^-6
should be written as 5.3 x 10^-6 ?
 
No, when displaying it should be written as 5.4x10-5, but for calculations you should use 5.388x10-5.

--
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
26
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
1
Views
1K