Silly math problem on precipitation

  • Thread starter yoshi6
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  • #1
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Hello everyone. I have this simple math problem that is worth 5 marks and I am not sure if it is right. Anyway it is on precipitation, here it is!

Record the amount of water (in centimetres) the tipping bucket rain gauge received. Calculate the total volume of water this would equal if this amount fell over the City of Guelph (area 86km squared). Is this volume greater or less than the average volume of water which flows through the city in the Spped River during a 24 hour period (average flow rate = 5.8mcubed per second).

Okay so first I am having trouble calculating the volume, I dont know why:

my recordings are: the amount of water (in centimetres) is four tenths of an inch--coverted equals 1.01600cm.

so, can I calculate this by multiplying 1.01600 x 86km

THANKS!!
 

Answers and Replies

  • #2
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pleaseeeee help!
 
  • #3
chemisttree
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I noticed that you didn't bother with the units in your calculation...
 
  • #4
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okay so here is my attempt...
convert---> 1.01600 to meters and 86 km squared to meters

and then... 0.01016 x 9270 x 9270 = 873, 078.3m^2 now to compare

24 hours in seconds/ 5.8m^2 per second= 86400/ 33.64=2568.37

So, therefore, the volume of water over Guelph city is greater than that of speed river.
 
  • #5
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can someone please be so kind and check this for me??? Thanks!
 
  • #6
chemisttree
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okay so here is my attempt...
convert---> 1.01600 to meters and 86 km squared to meters

and then... 0.01016 x 9270 x 9270 = 873, 078.3m^2 now to compare

24 hours in seconds/ 5.8m^2 per second= 86400/ 33.64=2568.37

So, therefore, the volume of water over Guelph city is greater than that of speed river.

You really need to focus on you units. This, for example, makes no sense.

24 hours in seconds/ 5.8m^2 per second= 86400/ 33.64=2568.37
 

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