Similarities / diffs between diffusion & wave propagation

Click For Summary
SUMMARY

This discussion clarifies the fundamental differences and similarities between diffusion and wave propagation as described by their respective equations: the diffusion equation and the wave equation. The diffusion equation, represented as ∇²Ψ = (1/c²)(∂²Ψ/∂t²), is first order in time and describes irreversible processes, such as heat conduction and ink diffusion. In contrast, the wave equation, D∇²u = ∂u/∂t, is second order in time and allows for both forward and backward propagating waves, demonstrating time-reversal symmetry. The solutions to these equations highlight that while both exhibit wave-like characteristics, they represent distinct physical phenomena.

PREREQUISITES
  • Understanding of differential equations, specifically the heat equation and wave equation.
  • Familiarity with concepts of time-reversal symmetry in physics.
  • Knowledge of macroscopic irreversible processes in thermodynamics.
  • Basic grasp of wave mechanics and energy dissipation.
NEXT STEPS
  • Study the derivation and applications of the heat equation in thermodynamics.
  • Explore time-reversal symmetry and its implications in wave mechanics.
  • Investigate dissipative processes and their mathematical representations in physics.
  • Learn about the physical interpretations of solutions to the wave equation and diffusion equation.
USEFUL FOR

Students in physics or engineering, educators teaching differential equations, and researchers interested in wave mechanics and thermodynamic processes will benefit from this discussion.

philmolz
Messages
2
Reaction score
0
Hi,

I'm a second year undergrad and we've covered the heat equation,

\begin{equation}
∇^{2}\Psi = \frac{1}{c^{2}}\frac{\partial^2 \Psi}{\partial t^2}
\end{equation}

and the wave equation,

\begin{equation}
D∇^{2}u= \frac{\partial u}{\partial t}
\end{equation}

in our differential equations course. Both Diffusion and wave propagation have wave like solutions, for example,

\begin{equation}
u= Ce^{-\sqrt{w/2D} x } \sin{(\sqrt{w/2D} x - wt)}
\end{equation}
\begin{equation}
\Psi = \Psi_{0} e^{i(kx-wt)}
\end{equation}

but are quite different phenomena. Could someone briefly explain the similarities/ differences in the phenomena and the solutions and how this relates to the differential equations please? Thanks.
 
Physics news on Phys.org
First, the difference in the equations themselves: The diffusion equation is first order in time, whereas the wave equation is second order. Now the solutions. The solution (3) to the diffusion equation is not a propagating wave, and is not a solution to the wave equation. Similarly, the solution (4) to the wave equation is not a solution of the diffusion equation.
 
That's great, thanks, but I thought (3) is a propagating wave that is attenuated with distance (propagating wave enveloped by a decaying exponential). Also, I was wondering what the physical difference between the two phenomena is that leads to the difference in the equations, ie why we don't just have a simple propagating wave solution for heat diffusion?
 
The wave equation (1) does not allow an attenuating solution. You can check that by substituting the attenuating function (3) into (1). Any solution of the wave equation is of the form f(x ± vt). The decaying solution is not of that form.
The difference between the two equations (and their solutions) is in time-reversal symmetry:
In equation (1), if you change t to - t, the equation is the same. That translates to the fact (easy to check) that both a forward propagating wave (unattenuated), and a backward propagating wave are solutions of the same equation, and are actually possible phenomena. You see both waves happening all the time.
The diffusion equation (2), on the other hand, is not invariant under time reversal. It represents a macroscopic irreversible process, for example, heat conduction from a high temperature region to a low temperature region, spreading of a drop of ink through a body of water, etc. these processes never happen in the reverse direction. These are inherently dissipative processes. The reverse processes (conduction from low to high temperature, the ink drop gathering back together) would violate the second law of thermodynamics. They are not solutions of the diffusion equation.
The attenuating "wave" is actually a dissipative process, in which energy is transferred from the "wave" into several other modes. That process is also irreversible, and is a solution of the diffusion equation.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 21 ·
Replies
21
Views
2K
Replies
13
Views
2K