Simple 2 level paramagnet system- How to find the number of states

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SUMMARY

The discussion focuses on calculating the number of states for a simple two-level paramagnet system with N non-interacting particles in an external magnetic field \(\vec{H}\). The Hamiltonian is defined as \(H = -h\sum^{N}_{i=1}{\sigma_{i}}\) with \(\sigma = \pm 1\) and \(h = -\mu |\vec{H}|\). The number of states \(\Omega\) is derived using the relation \(\Omega = \sum^{}_{\sigma}{\delta{(E-H)}}\), where the delta function is represented through its integral form. The solution involves approximating the integral and using the relationships \(E = (N_{up} - N_{down})(- \mu_{B}|\vec{H}|)\) and \(N_{up} + N_{down} = N\) to find \(\Omega = \frac{N!}{N_{up}!N_{down}!}\).

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Homework Statement


We have [itex]N[/itex] non interacting particles in external field [itex]\vec{H}[/itex]. The hamiltonian is given as [itex]H = -h\sum^{N}_{i=1}{\sigma_{i}}[/itex] with [itex]\sigma =\pm 1[/itex] and [itex]h = - \mu |\vec{H}|[/itex]. Calculate the number of states with given energy [itex]E[/itex] with help of this relation:

[itex]\Omega = \sum^{}_{\sigma}{\delta{(E-H)}}[/itex]

where [itex]\sum^{}_{\sigma}[/itex] represent summing over all configurations
Hint: Use Integral representation of delta function. Integrand can be written in form: [itex]exp[N f(k)][/itex]. Make a Taylor approximation of second order with respect to [itex]k[/itex] and solve integral.




Homework Equations


So, integral representation of delta function looks like that:
[itex]\delta(x) = \frac{1}{2\pi}\int^{\infty}_{-\infty}{exp(-ikx)}dx[/itex]

I'm asking for some hints, or advices, my main problem is that I'm not really sure how to handle that summation over all configurations and also, do we really need to play here with this delta function? We know that following is true:

[itex]E = (N_{up} - N_{down})(- \mu_{B}|\vec{H}|)[/itex]

and also [itex]N_{up} + N_{down} = N[/itex]

So if [itex]E[/itex] and [itex]N[/itex] are given, we can find out [itex]N_{up}[/itex]
and [itex]N_{down}[/itex] and from there we know that the number of all (to energy [itex]E[/itex]) corresponding configurations equals:

[itex]\Omega = \frac{N!}{N_{up}!N_{down}!}[/itex]

I'm sure i must be missing something, can someone be so kind and enlighten me:D
 
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The Attempt at a Solution So, integral representation of delta function looks like that:\delta(x) = \frac{1}{2\pi}\int^{\infty}_{-\infty}{exp(-ikx)}dxI'm asking for some hints, or advices, my main problem is that I'm not really sure how to handle that summation over all configurations and also, do we really need to play here with this delta function? We know that following is true:E = (N_{up} - N_{down})(- \mu_{B}|\vec{H}|)and also N_{up} + N_{down} = NSo if E and N are given, we can find out N_{up}and N_{down} and from there we know that the number of all (to energy E) corresponding configurations equals:\Omega = \frac{N!}{N_{up}!N_{down}!}I'm sure i must be missing something, can someone be so kind and enlighten me:D
 

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