Simple Algerbraic Manipulation is Confusing Me

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SUMMARY

The discussion centers on the algebraic manipulation of the Henderson-Hasselbalch equation, specifically in the context of calculating the % ionization of a weak acid or base. The equation in question is pH = pKa + log(A-/AH). The user successfully derived the expression A-/(AH + A-) by rearranging the original equation, moving A- to the left-hand side, adding 1 to both sides, converting to a single fraction, and then inverting the fractions before multiplying by 100. This step-by-step approach clarified the confusion regarding the algebraic process.

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mrlucky0
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I'm working on a chemistry problem and I'm trying to follow the derivation for % ionization (of a weak acid or base) but I can't seem to understand how rearrangement of eq. 6 results in eq. 7.

In more general terms, I started with the Hendreson Hasselbalch equation:

pH = pka + log(A-/AH)

What I want to find is, A-/(AH + A-)

This is giving me a real headache, can anyone help?
 

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Bring the A- to the LHS of (6). Add 1 to both sides and convert the LHS to a single fraction. Invert the fractions and multiply by 100.
 
Thanks, I've got it now.
 

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