The uranium isotope 235U captures a neutron and undergoes fission to produce 93Rb and 141Cs. Calculate the energy released in this process.
The nuclear masses of the relevant isotopes are
The Attempt at a Solution
The answer is given as
n + 235U → 93Rb + 141Cs + 2n
LHS 235.0439 + 1.0087
RHS 92.921712 + 140.91949 + 2.10087
Difference is 0.1943u = 181 MeV
I realise the quantity of 1.0087 is the mass of neutron divided by one unified atomic mass unit. So that's (1.67493 x 10^-27) / (1.66 x 10^-27).
Also, the 2.10087 number is simply double this.
How have the 235.0439, 92.921712 & 140.91949 values been calculated? I know it's to do with E=Mc^2