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## Homework Statement

The uranium isotope 235U captures a neutron and undergoes fission to produce 93Rb and 141Cs. Calculate the energy released in this process.

The nuclear masses of the relevant isotopes are

235U 235.0439u,

93Rb 92.9217u,

141Cs 140.9195u

## Homework Equations

## The Attempt at a Solution

The answer is given as

n + 235U → 93Rb + 141Cs + 2n

LHS 235.0439 + 1.0087

RHS 92.921712 + 140.91949 + 2.10087

Difference is 0.1943u = 181 MeV

I realise the quantity of 1.0087 is the mass of neutron divided by one unified atomic mass unit. So that's (1.67493 x 10^-27) / (1.66 x 10^-27).

Also, the 2.10087 number is simply double this.

How have the 235.0439, 92.921712 & 140.91949 values been calculated? I know it's to do with E=Mc^2

Thank you.