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Homework Help: Simple Capacitor Problem making a Big Problem

  1. Apr 11, 2010 #1
    1. The problem statement, all variables and given/known data
    attachment.php?attachmentid=25037&stc=1&d=1271004346.gif
    Given the two capacitors, in what way should you connect them to get the greatest potential difference over the whole construction?

    2. Relevant equations
    More a concept question, no relevant equations (except definition C = Q/V)

    3. The attempt at a solution
    Okay I know I'm supposed to think that if you connect "2" to "4" (or "1" to "3") you get a total potential difference of 5 + 5 = 10 V. But I'm having trouble truly seeing that they just add. When you connect "2" to "4", they're clearly on a different potential, and because it's a conductor, it'll want to go into electrostatic equilibrium and make the two connected pieces the same voltage, resulting in a shift of charges.

    If you say "the uttermost left and uttermost right halves keep the charges in the middle where they are so they don't mix and change things", I understand, but still, then what is the deal with the (in this explanation non-existing) equipotential surface. So my clear question is: on one hand I understand that the capacitor-charge distribution (of each) doesn't change upon connection of "2" and "4", but on the other hand I don't understand, because there should be an equipotential surface (created) in between. What's the big picture?

    I thank you,
    mr. vodka
     

    Attached Files:

  2. jcsd
  3. Apr 11, 2010 #2
    Is it maybe that there IS a shift of charges to make it an equipotential surface, but that it's pretty much negligable? That does sound pretty qualitative and even vague...
     
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