- #1

Kaushik

- 282

- 17

- Homework Statement
- The parallel combination of two air filled parallel plate capacitors of capacitance ##C## and ##nC## is connected to a battery of voltage, ##V##. When the capacitors are fully charged, the battery is removed and after that a dielectric material of dielectric constant ##K## is placed between the two plates of the first capacitor. The new potential difference of the combined system is?

- Relevant Equations
- ##Q = CV##

##C_{eq}= C_1 + C_2## for parallel

## \frac{1}{C_{eq}}= \frac{1}{C_1} + \frac{1}{C_2}## for series

First when it is connected to the battery, the capacitors start accumulating charges such that the potential difference equals that of the battery. Then the current stops flowing.

##Q_1 = CV##

##Q_2 = nCV##

Where 1 and 2 represent the capacitor with capacitance C and nC respectively

Then, when we remove the battery and add a dielectric between the capacitor of capacitance ##C## (##C_{new} = KC##), the potential difference across it reduces. Now, the capacitor 2 starts behaving like a battery, providing charge to the capacitor 1.

After this, how can I proceed?

##Q_1 = CV##

##Q_2 = nCV##

Where 1 and 2 represent the capacitor with capacitance C and nC respectively

Then, when we remove the battery and add a dielectric between the capacitor of capacitance ##C## (##C_{new} = KC##), the potential difference across it reduces. Now, the capacitor 2 starts behaving like a battery, providing charge to the capacitor 1.

After this, how can I proceed?