1. The problem statement, all variables and given/known data For the function f(x) = 1/4 (x=2)^2 - 4, i'm confused with regards to finding x & y intercepts. 2. Relevant equations 3. The attempt at a solution You can work them out from the function in its current form, i think? For y-int, let x=0, which leaves (0,-3). For x-nt, i done as follows; 1/4 (x+2)^2 = 4 (x+2)^2 = 16 x+2 = [tex]\pm[/tex] 4 x=2, x= -6 But then also one could use the quadratic formula, working from 1/4 (x^2 +4x +4) -4 1/4x^2 + x -3 Which gives intercepts 3/2, and -1/2 And also f(4x)= (x+2)^2 - 16 = x^2 + 4x - 12 =(x-2)(x+6) 4x=2, 4x= -6 x=1/2, x= -3/2 So, 3 different sets. What am i missing? I mean, i'm certain that the vertex lies at (-2,-4), so x=2, x=-6 must be the correct intercepts - but why are the others wrong? Thanks.