Simple minimum/maximum problem

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Homework Help Overview

The discussion revolves around a mathematical problem involving the relationship between voltages in a high-pressure transmitting line, expressed through a trigonometric equation. Participants are tasked with expanding and manipulating this equation to find maximum and minimum values related to the parameters involved.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss expanding the given equation and expressing terms in a specific trigonometric form. There is a focus on how to derive the values of R and α from the equation involving a cos(θ) + b sin(θ). Some participants question the correctness of the methods used in the expansions and transformations.

Discussion Status

The discussion is ongoing, with participants providing different perspectives on how to approach the problem. Some guidance has been offered regarding the correct form to use for expressing the trigonometric terms, and there is an exploration of relationships between the coefficients a and b.

Contextual Notes

Participants are navigating the constraints of the problem as stated, including the specific requirement to express a cos(θ) + b sin(θ) in a particular form, which has led to some confusion and differing interpretations of the task.

John O' Meara
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The voltage E applied to the sending end of a high-pressure transmitting line is connected to the voltage e at the receiving end by the equation [tex]E^2 = ( e cos \theta + a)^2 + ( e sin\theta +b)^2\\[/tex], where a and b are constants.
Expand the right-hand side of this equation and by expressing [tex]a cos\theta + b sin\theta \\[/tex] in the form [tex]R cos(\theta + \alpha) \\[/tex] show that the maximum and minimum values of R as [tex]\theta[/tex] varies , are e +/- [tex]\sqrt{a^2 +b^2} \\[/tex]. ( obtaining these results by differentation is a much more difficult method and we would remind our readers that the calculus is not always the best way of solving a problem.
Expanding this I get: [tex]E^2= e^2 cos^2\theta +a^2 +2ae cos\theta + e^2 sin^2\theta + 2eb sin\theta +b^2 \\[/tex], which gives [tex]E^2 = e^2 +2e(a cos\theta + b sin\theta ) +a^2 + b^2 \\[/tex], which can be expressed as
[tex]e^2 + 2e(a cos\theta + b cos(\frac{\pi}{2} - \theta) ) + a^2 + b^2[/tex]. The thing is I do not know how to express R in terms of the coefficients a and b? Thanks for the help.
 
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You didn't do what you were asked to do.

You rewrote [itex]\sin\theta[/itex] as [itex]\cos(\pi/2-\theta)[/itex]. That is not what the problem says to do. The problem specifically says to write [itex]a\cos\theta+b\sin\theta[/itex] in the form [itex]R\cos(\theta+\alpha)[/tex]. Simply expand this latter form, equate to [itex]a\cos\theta+b\sin\theta[/itex], and solve for [itex]R[/itex] and [itex]\alpha[/itex].[/itex]
 
Expanding R [tex]cos(\theta + \alpha) \\[/tex] we get[tex]R( \cos\theta \sin\alpha - \sin\theta \sin\alpha) \\[/tex]. Now [tex]R \cos\theta\cos\alpha - R \sin\theta\sin\alpha = a \cos\theta + b \sin\theta \\[/tex] When [tex]\theta = 0 R = \frac{a}{\cos\alpha} \\[/tex] When [tex]\theta = \frac{\pi}{2} R = \frac{-b}{\sin\alpha}\\[/tex] Therefore [tex]\tan\alpha = \frac{-b}{a}[/tex]. I would appreciate help in getting R.
 
Last edited:
Ok, so a=R*cos(alpha) and b=-R*sin(alpha). Square and add both of those equations and use everybodies favorite trig identity.
 

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