Simple Momentum Question: Calculating Y-Direction After Given Angles

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SUMMARY

The discussion centers on calculating the y-direction momentum components using the formula p=mv, where mass is 1 unit. Participants analyze two scenarios involving distances and angles: the first scenario with a distance of 9.4 cm at 34 degrees north of west, and the second with a distance of 14.7 cm at 94 degrees east of north. The calculations involve using sine functions to derive the y-components of momentum, specifically 9.4sin34 and 14.7sin93. The conversation emphasizes the importance of clearly stating the problem for effective resolution.

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oridniv
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So, we were given a scenario and were asked to not calculate the momentum components in the x- directions. We were asked to use the simple formula of momentum(p) p=mv. Velocity was the root of the distance between the collisions and the mass was 1 unit. No specific units are to be used in these calculations. The question asks us to calculate momentum in the y-direction after being given specific angles. What's the difference between the distance and the y- component again?
 
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It'll be easier for someone to answer if you state the exact question you are trying to solve, along with the work you have done on it (i.e. what you have calculated)
 
1st scenario:
d=9.4cm
v= square root d= 3.1
I don't know how to calculate the y-components of momentum considering on an x-y plane, d is 34 degrees north of west. What I calculated was 9.4sin34 to get the y components but I can't shake the feeling that I might be wrong

2nd scenario, same as first but different numbers
d=14.7
v=3.83
d is 94 degrees east of north
y-component=14sin93
 
Could you state the whole question as given. It is quite confusing to me now.
 
don't worry, my prof explained and it now makes sense, thanks tho
 

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