Simple quantum mechanics operator question

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Homework Help Overview

The discussion revolves around identifying the physical quantity represented by the operator iħ∂/∂t within the context of quantum mechanics, specifically relating to the Schrödinger equation.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between the operator and the Hamiltonian, questioning whether it represents total energy for a free particle and discussing the broader applicability of the Schrödinger equation.

Discussion Status

Some participants have provided insights regarding the operator's connection to the Hamiltonian and its interpretation as energy, while others are seeking clarification on its specific form and implications in different contexts.

Contextual Notes

There is mention of a specific Hamiltonian for a free particle, which raises questions about the generality of the operator in various quantum scenarios.

Chowie
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Homework Statement



What physical quantity is represented by the operator [itex]i\bar{h}∂/∂t[/itex]

Homework Equations



[itex]i\bar{h}∂/∂t[/itex]


The Attempt at a Solution



It's a one mark question, I just have no idea what it is and I can't find it in my notes D:.
 
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Look at the Schrödinger equation.
 
Is it total energy for a free particle?
 
Chowie said:
Is it total energy for a free particle?

The Schrödinger equation applies to more than just free particles. But yes, it's the Hamiltonian. So I think it would be fair to call it the energy.
 
Hmm, I have the hamiltonian written down here as

[itex]\hat{H}=-\frac{\bar{h}^{2}}{2m}∂^{2}/∂x^{2}[/itex]


So that is also equal to [itex]i\bar{h}∂/∂t[/itex] ?

[itex]\vec{}[/itex]
 
Chowie said:
Hmm, I have the hamiltonian written down here as

[itex]\hat{H}=-\frac{\bar{h}^{2}}{2m}∂^{2}/∂x^{2}[/itex]


So that is also equal to [itex]i\bar{h}∂/∂t[/itex] ?

[itex]\vec{}[/itex]

That's the Hamiltonian for a free particle in one dimension. It's a special case. Your operator is the Hamiltonian even in cases where that is not the Hamiltonian.
 

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