Simple question about parametric equations of a plane in 3D

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In a 3D space, the equation z=2 represents a horizontal plane where x and y can take any values, meaning they are not constrained to specific parameters like x=t and y=t. The discussion clarifies that a plane requires two parameters, while a line requires one. Introducing a third parameter would fill the entire 3D space, not just a plane. The confusion with Wolfram Alpha arises because it defaults to showing a line instead of the full plane representation. The initial assumption about the parameters was incorrect; x and y should remain independent.
ainster31
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I'm quite rusty in Linear Algebra.

If you have a plane in 3D with the equation ##z=2##, what does ##x## and ##y## equal? Does ##x=t## and ##y=t##?

Because if I graph that in Wolfram Alpha, I don't get a horizontal plane in 3D at ##z=2##: http://www.wolframalpha.com/input/?i=graph+z=2,x=t,y=t
 
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hi ainster31! :smile:
ainster31 said:
If you have a plane in 3D with the equation ##z=2##, what does ##x## and ##y## equal? Does ##x=t## and ##y=t##?

line: one parameter

plane: two parameters :wink:

your plane is z = 2, x = t, y = u​
 
tiny-tim said:
hi ainster31! :smile:line: one parameter

plane: two parameters :wink:

your plane is z = 2, x = t, y = u​

Hmm... what about 3 parameters? What would that result in? A filled 3D cube, right?
 
If x, y, and z are arbitrary, you get the entire space (all of R3).
 
ainster31 said:
Hmm... what about 3 parameters? What would that result in? A filled 3D cube, right?

3 dimensions: 3 parameters …

n dimensions: n parameters …

that's very nearly a definition of dimensions! :smile:
 
z=2 is the equation of a plane in R^3. x and y range over R since they are not specified. So you essentially end up with an x,y plane. In wolfram alpha they just show a line since there doesn't appear to be an easy way to tell it you want R^3. Your initial assumption was correct and variable t shouldn't be introduced.
 
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