Simple recoil velocity question

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In summary, a cannon with a mass of 1500 kg fires a 10 kg shell with a velocity of 200 m/s at an angle of 45 degrees above the horizontal. To find the recoil velocity of the cannon across level ground, the conservation of momentum equation is used, where the initial velocities of the cannon and cannon ball are both at rest. Plugging in the given values, the final velocity of the cannon is calculated to be -1.33 m/s. However, to find the velocity of the cannon along the ground, the component of the velocity at the given angle must be calculated. The correct answer is 0.94 m/s, which can be found by using the component of velocity in the given angle.
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LIZard137
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Homework Statement


A cannon of mass 1500 kg fires a 10 kg shell with a velocity of 200 m/s at an angle of 45 degrees above the horizontal. Find the recoil velocity of the cannon across the level ground.


Homework Equations


Conservation of Momentum equation:
0=m1v1f + m2v2f
v1f = - (m2/m1)(v2f)


The Attempt at a Solution



Ok so I'm having trouble with this problem. I could've sworn I was doing it correctly, but here it goes. Because the cannon and the cannon ball are both at rest, initial velocities don't play a part in this question (I think?). So plugging in the numbers into the equation I got:

M1 = 1500
M2 = 10
V2f = 200

V1f = - (10/1500)(200) = -1.33 m/s

The anwser to this question is 0.94 m/s, and I can't figure out what I'm doing wrong for the life of me. Any push in the right direction would be awesome!
 
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  • #2
the thing is ... use just m1v1+m2v2=0 and then find out the velocity of the cannon..
Now the question asked is to find the velocity of the cannon along the ground... so what you have to do is find the component of velocity in the angle given.

Anyway , your answer is partly correct.. you just got to do the component part.
 

Related to Simple recoil velocity question

1. What is simple recoil velocity?

Simple recoil velocity is the velocity at which an object moves in the opposite direction when it is subjected to a recoil force. It is a result of the conservation of momentum principle.

2. How is simple recoil velocity calculated?

Simple recoil velocity is calculated by dividing the momentum of the recoiling object by its mass. The momentum can be calculated by multiplying the mass of the object by its initial velocity.

3. What factors affect the magnitude of simple recoil velocity?

The magnitude of simple recoil velocity is affected by the mass of the object, the velocity of the object before recoil, and the strength of the recoil force.

4. Can simple recoil velocity be negative?

Yes, simple recoil velocity can be negative if the recoil force is greater than the initial velocity of the object. This means the object will be moving in the opposite direction with a velocity that is smaller in magnitude.

5. How is simple recoil velocity used in real-life applications?

Simple recoil velocity is used in various real-life applications such as firearms, rockets, and jet engines. It is also important in understanding the behavior of objects in collisions and explosions.

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