Simple relationship equation major headache

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Ronb107
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Homework Statement


The quantity p varies directly with the cube of q and inversely
with the square of r. If p = 3/2, q = 1/2, and r = 1/3, which of the
following equations represents the relationship between p, q,
and r?


Homework Equations


Here's what I did...
(3/2)p = (1/2)q^3 / (1/3)r^2


The Attempt at a Solution


Could not get the answer, which is: p = (4q^3) / (3r^2)

Thanks for your help.

 
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Ronb107 said:
(3/2)p = (1/2)q^3 / (1/3)r^2
You are quite right to write down an equation of the form p = Aq3/r2, but you have not used the other information correctly. You need to find the value of A such that the given values of p, q and r are a solution to the equation.
 
Ronb107 said:

Homework Statement


The quantity p varies directly with the cube of q and inversely
with the square of r. If p = 3/2, q = 1/2, and r = 1/3, which of the
following equations represents the relationship between p, q,
and r?

Homework Equations


Here's what I did...
(3/2)p = (1/2)q^3 / (1/3)r^2

The Attempt at a Solution


Could not get the answer, which is: p = (4q^3) / (3r^2)

Thanks for your help.

You've got the basic relation right. All that's missing is an unknown constant k. So p=kq^3/(r^2). Just put the given values in for p, q and r and solve for k.