Are All Gauge Groups in the Standard Model Semisimple for a Physical Reason?

Click For Summary
SUMMARY

All gauge groups in the Standard Model (SM), including U(1), are semisimple due to the necessity of maintaining a positive definite norm for quantum states, which is essential for the probability interpretation of quantum mechanics. Nonsemisimple groups risk introducing negative norm states, as their Killing forms are not definite. While constraints can be applied to eliminate these negative norm states in certain theories, the discussion emphasizes that solvable Lie algebras, apart from abelian ones, pose challenges due to the vanishing Killing form on the derived subalgebra, leading to unphysical zero norm states.

PREREQUISITES
  • Understanding of gauge groups in the Standard Model
  • Familiarity with the concept of positive definite norms in quantum mechanics
  • Knowledge of the Killing form and its implications in Lie algebras
  • Basic principles of gauge invariance and its applications
NEXT STEPS
  • Research the properties of semisimple Lie algebras and their significance in quantum field theory
  • Explore the implications of the Killing form in nonsemisimple groups
  • Learn about constraints used to eliminate negative norm states in quantum theories
  • Investigate solvable Lie algebras and their role in theoretical physics
USEFUL FOR

The discussion is beneficial for theoretical physicists, particularly those specializing in quantum field theory, gauge theories, and the mathematical foundations of particle physics.

fresh_42
Staff Emeritus
Science Advisor
Homework Helper
Insights Author
2025 Award
Messages
20,815
Reaction score
28,445
Is there a physical reason why all gauge groups considered in SM and especially beyond are always semisimple? [+ U(1)] What would happen if they were solvable?
 
Physics news on Phys.org
The norm of a quantum state must be positive definite in order that the probability interpretation of quantum mechanics makes sense. For a nonsemisimple group, the Killing form is not definite, so we can't guarantee that there won't be any negative norm states. There are ways to use constraints to remove the negative norm states for certain theories. A simple example is the way that gauge invariance can be used to remove the negative norm states from the ##SO(d,1)## metric on a massless vector field.

I'm not sure about solvable Lie algebras other than the abelian ones. Since the Killing form vanishes on the derived subalgebra, there will be zero norm states that would be considered unphysical. Perhaps one could find suitable constraints to project these out.
 
  • Like
Likes   Reactions: David Horgan
Thank you.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 0 ·
Replies
0
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 26 ·
Replies
26
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
1
Views
1K
  • · Replies 27 ·
Replies
27
Views
9K
  • · Replies 8 ·
Replies
8
Views
3K