Simplification of an equation based on exponent rules

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SUMMARY

The discussion centers on simplifying the expression $$\frac{5 + \sqrt{5}}{2\sqrt{5}} \cdot \left(\frac{1 + \sqrt{5}}{2}\right)^{x}$$ to the form $$\left(\frac{1 + \sqrt{5}}{2}\right)^{x+1}$$. The simplification is achieved by recognizing that $$\frac{5 + \sqrt{5}}{2\sqrt{5}}$$ simplifies to $$\frac{1 + \sqrt{5}}{2}$$ when the numerator and denominator are multiplied by $$\sqrt{5}$$. The discussion emphasizes the importance of correct terminology, distinguishing between expressions and equations, and highlights the need for clarity in mathematical communication.

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ATroelstein
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I have the following equation that I'm trying to simplify:

$$\frac{5 + \sqrt{5}}{2\sqrt{5}}*(\frac{1 + \sqrt{5}}{2})^{x}
$$

From looking at it, it seems like it could be simplified so that the right-hand side of the multiplication would be:

$$(\frac{1 + \sqrt{5}}{2})^{x+1}
$$

I started to pull the left-hand side apart to get a match to the right-hand side and ended up with:

$$
(\frac{4}{2\sqrt{5}} + \frac{1}{\sqrt{5}} * \frac{1+\sqrt{5}}{2}) * (\frac{1 + \sqrt{5}}{2})^{x}
$$

From here, I'm starting to wonder if my initial observation was flawed. Is there a way to simplify this is terms of:

$$(\frac{1 + \sqrt{5}}{2})^{x+1}
$$

Thanks.
 
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$ \displaystyle \frac{5 + \sqrt{5}}{2 \sqrt{5}}$ = $\displaystyle \frac{1 + \sqrt{5}}{2}$ by multiplying numerator and the denominator by $$\sqrt{5}$$

Hence, the multiplication of it with $$\left ( \frac{1 + \sqrt{5}}{2} \right )^x$$ is equal to $$\left ( \frac{1 + \sqrt{5}}{2} \right )^{x+1}$$
 
First, I want to say that what you have is an expression, not an equation. An equation gives the equality between two expressions, and is identified by the use of the "=" sign. I have seen many student confuse the two terms. :D

This may seem like a trivial point to make, but in order to be able to communicate effectively in any subject, the correct use of terminology is crucial.

Your expression consists ot two factors. Look at the factor on the left:

$$\frac{5+\sqrt{5}}{2\sqrt{5}}$$

Can you factor the numerator, so that you may cancel with a factor in the denominator?

I now see I have been pipped at the post, but do you see how mathbalarka simplified the factor on the left?
 

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