MHB Simplification of an equation based on exponent rules

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The equation presented for simplification is $$\frac{5 + \sqrt{5}}{2\sqrt{5}}*(\frac{1 + \sqrt{5}}{2})^{x}$$. It can be simplified to $$\left(\frac{1 + \sqrt{5}}{2}\right)^{x+1}$$ by recognizing that $$\frac{5 + \sqrt{5}}{2\sqrt{5}}$$ simplifies to $$\frac{1 + \sqrt{5}}{2}$$. The discussion emphasizes the importance of terminology, noting that the expression is not an equation since it lacks an equality sign. Additionally, it suggests factoring the numerator to facilitate cancellation with the denominator. The overall conclusion is that the expression can indeed be simplified as initially suspected.
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I have the following equation that I'm trying to simplify:

$$\frac{5 + \sqrt{5}}{2\sqrt{5}}*(\frac{1 + \sqrt{5}}{2})^{x}
$$

From looking at it, it seems like it could be simplified so that the right-hand side of the multiplication would be:

$$(\frac{1 + \sqrt{5}}{2})^{x+1}
$$

I started to pull the left-hand side apart to get a match to the right-hand side and ended up with:

$$
(\frac{4}{2\sqrt{5}} + \frac{1}{\sqrt{5}} * \frac{1+\sqrt{5}}{2}) * (\frac{1 + \sqrt{5}}{2})^{x}
$$

From here, I'm starting to wonder if my initial observation was flawed. Is there a way to simplify this is terms of:

$$(\frac{1 + \sqrt{5}}{2})^{x+1}
$$

Thanks.
 
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$ \displaystyle \frac{5 + \sqrt{5}}{2 \sqrt{5}}$ = $\displaystyle \frac{1 + \sqrt{5}}{2}$ by multiplying numerator and the denominator by $$\sqrt{5}$$

Hence, the multiplication of it with $$\left ( \frac{1 + \sqrt{5}}{2} \right )^x$$ is equal to $$\left ( \frac{1 + \sqrt{5}}{2} \right )^{x+1}$$
 
First, I want to say that what you have is an expression, not an equation. An equation gives the equality between two expressions, and is identified by the use of the "=" sign. I have seen many student confuse the two terms. :D

This may seem like a trivial point to make, but in order to be able to communicate effectively in any subject, the correct use of terminology is crucial.

Your expression consists ot two factors. Look at the factor on the left:

$$\frac{5+\sqrt{5}}{2\sqrt{5}}$$

Can you factor the numerator, so that you may cancel with a factor in the denominator?

I now see I have been pipped at the post, but do you see how mathbalarka simplified the factor on the left?
 
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Obviously, there is something elementary I am missing here. To form the transpose of a matrix, one exchanges rows and columns, so the transpose of a scalar, considered as (or isomorphic to) a one-entry matrix, should stay the same, including if the scalar is a complex number. On the other hand, in the isomorphism between the complex plane and the real plane, a complex number a+bi corresponds to a matrix in the real plane; taking the transpose we get which then corresponds to a-bi...

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