- #1

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## Main Question or Discussion Point

I am trying to work through a simplication of this factorial with variables:

(n/2)!/[(n+2)/2]!

I get,

2[n(n-1)]/2[(n+2)(n+1)n(n-1)]

cancelling the 2[n(n-1)]

leaves me with 1/[(n+2)(n+1)]

However, Wolfram Alpha tells me this can be simplified as 2/(n+2) and I don't see that.

Thanks

(n/2)!/[(n+2)/2]!

I get,

2[n(n-1)]/2[(n+2)(n+1)n(n-1)]

cancelling the 2[n(n-1)]

leaves me with 1/[(n+2)(n+1)]

However, Wolfram Alpha tells me this can be simplified as 2/(n+2) and I don't see that.

Thanks