Simplifying GR: Algebraic Solutions Explained

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SUMMARY

The discussion focuses on the algebraic manipulation of tensors in general relativity, specifically the relationship between the metric tensor components \( g_{\bar{i}\bar{j}} \) and the transformation matrix \( \Lambda \). It is established that the expression \( g_{\bar{i}\bar{j}} = \Lambda_{\bar{i}}^{i} \Lambda_{\bar{j}}^{j} g_{ij} \) can be rewritten as \( g_{\bar{i}\bar{j}} = (\Lambda^T g \Lambda)_{\bar{i}\bar{j}} \). The derivation relies on the properties of matrix multiplication and transposition, demonstrating that the transformation of the metric tensor under a change of coordinates can be systematically shown rather than merely inspected.

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  • Understanding of tensor notation and operations in general relativity
  • Familiarity with matrix multiplication and properties of transposes
  • Basic knowledge of linear algebra concepts
  • Experience with metric tensors and their transformations
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  • Study the properties of tensor transformations in general relativity
  • Learn about the role of the metric tensor in curved spacetime
  • Explore advanced matrix operations, including Kronecker products
  • Investigate the implications of coordinate transformations on physical quantities
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Students and researchers in physics, particularly those focusing on general relativity, as well as mathematicians interested in tensor analysis and linear algebra applications in theoretical contexts.

proguinn
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This isn't homework but since it's a simple algebra thought I suppose it's the most appropriate forum- I'm working through some basic general relativity and just came across a line i think I'm being stupid about:

<br /> g_{\bar{i}\bar{j}}=\Lambda_{\bar{i}}_{i}\Lambda_{\bar{j}}_{j} g_{ij}<br />

then, it's said that it's obvious that this means:
<br /> g_{\bar{i}\bar{j}}= (\Lambda^T g \Lambda)_{\bar{i}\bar{j}}<br />

Is there an easy way to show this, other than by inspection?

thanks.
 
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If A and B are matrices, then the matrix product is given by
(AB)ik = Aij Bjk
by definition, and the transpose of A is given by
(AT)ij = Aji

From that it easily follows (just write them in the correct order, then swap the indices on one of them creating a transpose).
 

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