The discussion revolves around simplifying an expression involving rational and negative exponents. Participants are working through the algebraic manipulation of the expression, which includes terms with variables raised to fractional powers.
Some participants have confirmed the expression's form and are discussing potential methods for simplification. There is an ongoing exploration of how to approach the problem, with suggestions for separating terms to facilitate the simplification process.
One participant notes the importance of parentheses in the expression, indicating that clarity in the setup is crucial for further simplification. There is also a mention of avoiding conversion to radicals at an early stage, suggesting a preference for working with exponents directly.
Although you have used lots of parentheses, for which you are to be applauded, you might be missing the most important pair.scarne92 said:Homework Statement
Simplify the expression completely
3(y)(1/3)-3x(y)(-2/3)(2x) / [(y)(1/3)]2
It's not a good idea to convert to radicals at this point.scarne92 said:The Attempt at a Solution
My attempt is totally wrong. I can't quit figure out what to do or where to start
3(y)(1/3)-3x(y)(-2/3)(2x) / [(y)(1/3)]2
3(y)(1/3)-6x(y)(-2/3) / y(2/3)
3√[3(y)(1/3)-6x(y)(-2/3) / y(2/3)]
3√(3) y - 3√(6x) y-2 / y2
scarne92 said:3√(3) y - 3√(6x) / y4
3√3 - 3√6x / y3
(3√3 - 3√6x / y3)3
(3-6x) / y9
scarne92 said:$$ \frac{3y^{1/3} - 3xy^{-2/3}2x}{y^{2/3}}$$
yes that is the expression, I couldn't get the LaTex to work properly, but yes.