Simplifying (x² - 6x + 4) / ((x² - 4)(x - 2))

  • Thread starter Thread starter danni7070
  • Start date Start date
  • Tags Tags
    Simplifying
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
8 replies · 2K views
danni7070
Messages
91
Reaction score
0
How do I simplify this?

[tex]\frac{1}{x-2} - \frac{1}{x^2-4} = \frac{(x^2-4)-(x-2)}{(x^2-4)(x-2)}[/tex]
 
Physics news on Phys.org
Combine the 4 and 2 in the numerator so you have a single quadratic. Then see if it factors so you can see of if there are any common factors you can cancel.
 
[tex]\frac{x^2-x-2}{(x^2-4)(x-2)}[/tex]

I know I should be able to see this instantly but I'm not! What comes next?
 
You don't have to see it instantly. Can you factor the numerator?
 
Like this?

[tex]\frac{x^2-x-2}{(x-2)(x+2)(x-2)}[/tex]
 
Last edited:
[tex]\frac{x^2-x-2}{(x-2)^2(x+2)} = \frac{x+1}{(x-2)(x+2)}[/tex]

The final step is the answer but I don't know how to get there. What are the rules here?
 
danni7070 said:
Like this?

[tex]\frac{x^2-x-2}{(x-2)(x+2)(x-2)}[/tex]


after this stage

factor the numerator

x2 - x - 2 = (x-2)(x+1)

right?

then u can cancel t he (x-2) in the numerator and denominator and ur left with that answer that ur looking for
 
I'm having one of those dumb days right know. Jesus!

Thank you Dick and salman213.
 
danni7070 said:
Like this?

[tex]\frac{x^2-x-2}{(x-2)(x+2)(x-2)}[/tex]
They said factor the numerator! (Although factoring the denominator doesn't hurt.)