Sin^5(x)+Cos^5(x) Equation Solution for Mathematicians

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Discussion Overview

The discussion revolves around solving the equation Sin^5(x) + Cos^5(x) given that Sin(x) + Cos(x) = 1/3. Participants explore various mathematical approaches and identities related to the problem, including symmetric functions and algebraic manipulations.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant requests the original poster (OP) to show their work, emphasizing that homework problems should be posted in designated forums.
  • Another participant presents the identity for the sum of fifth powers, suggesting a potential method for solving the problem.
  • A subsequent reply corrects a sign error in the identity presented, indicating a need for precision in mathematical expressions.
  • One participant introduces variables u and v to represent Sin(x) and Cos(x), respectively, and discusses the implications of knowing their sum and product for deriving Sin^5(x) + Cos^5(x).
  • Another participant calculates Sin(2x) based on the given condition, suggesting a pathway to find x and subsequently Sin^5(x) + Cos^5(x).

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the approach to solving the problem, with multiple methods and corrections being proposed. The discussion remains unresolved regarding the final solution.

Contextual Notes

There are limitations in the discussion, including assumptions about the values of Sin(x) and Cos(x) and the dependence on the identities used. Some mathematical steps remain unresolved, particularly in the context of deriving Sin^5(x) + Cos^5(x) from the given condition.

hadi amiri 4
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if sin(x)+cos(x)=1/3 then Sin(x)^5+Cos(x)^5=?
 
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What do you think it is? We do not do your homework for you here. Show some work, please.

One more thing: Please post homework problems in one of the homework forums.
 
x5+ y5= (x+ y)(x4- x3y+ x2y2+ xy3+ y4)
 
HallsofIvy said:
x5+ y5= (x+ y)(x4- x3y+ x2y2+ xy3+ y4)

You have a sign error, Halls.
5+ y5= (x+ y)(x4- x3y+ x2y2- xy3+ y4)
 
Let u=sin(x) v=cos(x). We know u+v, and since (u+v)^2=1+2uv, we know uv, hence we know a basis of the symmetric functions in u,v, and we can, if we are bothered work out, u^5+v^5. That I feel is far less interesting than the knowledge about symmetric function theory...

But the OP seems to be posting all these questions as challenges, rather than questions for which he seeks the answer.
 
sin(x)+cos(x)=1/3 then 1+2sin(x)cos(x)=1/9= 1+sin(2x)

so sin(2x)=-8/9 then 2x=arcsin(-8/9) once you have got 'x' the rest is easy
 

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