Sine wave & reflection question?

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It is possible to manipulate a sine wave by adding another wave, but adding a cosine wave with a higher amplitude does not simply convert the sine wave into a cosine wave. Specifically, the equation sin(x) + 2cos(x) does not equal cos(x), as this would imply sin(x) = -cos(x), which is incorrect. For a clearer understanding of wave interactions and reflections, resources like HyperPhysics and PhET are recommended. The discussion emphasizes the need for precise amplitude adjustments to achieve desired wave transformations. Understanding these principles is crucial for studying wave behavior in physics.
shintashi
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I seem to recall it is possible to change a wave's frequency, pattern, and amplitude by adding another wave to it.

Is it possible to add a second wave to a Sine wave to turn it into a cosine wave of the same amplitude and how would you do this? I'm thinking if I had an amplitude 1 for the sinewave, an amplitude 2 cosine wave would wipe out the sine wave and be reduced to a cosine wave. Is there a simpler way of doing this requiring less amplitude?

As a side note on waves, is there a good place/website to understand the physics behind reflection?
 
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This is a question, not "learning materials" so I am moving this to "Introductory Physics".
 
So you think sin(x)+2cos(x) = cos(x)?

If this were true, then sin(x) = -cos(x) would also be true (which it isn't). What you're probably thinking of is the http://physics.tamuk.edu/~suson/html/4323/super.html.

I'm not sure what specifically you're looking for in regards to reflection (sound? light? mechanical waves?), but a couple of sites that have been handy for me are hyperphysics and PhET (I seem to recall a simulation or two involving waves/pulses on a string)
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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