The discussion centers on calculating the angle at which 750nm light produces a second minimum through a single slit with a width of 2.0μm. The relevant equation is Sin(theta) = n(lambda)/w, where n is the order of the minimum. The user incorrectly inputs 3x10^-6 for the numerator, leading to a sine value greater than 1, which is mathematically impossible. The correct angle for the second minimum is 49 degrees, derived from the proper application of the equation.
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Quantum Fizzics said:Homework Statement
At what angle will 750nm light produce a second minimum if the single-slit width is 2.0um
Homework Equations
Sin(theta)=n(lambda)/w
The Attempt at a Solution
This is what I got so far
(theta)=sin-1(3x10^-6/2x10^-6)
the answer btw is 49degrees
It's because you are asking for an angle with sin > 1.Quantum Fizzics said:I don't understand why I keep getting error on my calculator