Size of Force between two Point Charges

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SUMMARY

The discussion centers on calculating the force between two point charges: +2.0 microC and -0.35 microC, separated by 4.0 x 10-4 m. Using the formula F = 1/(4 pi ε0) x (q1 x q2 / r2), the calculated force is -3.9 x 104 N. The negative sign indicates that the charges attract each other, confirming the direction of the force.

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Homework Statement


A point charge of +2.0 microC is separated from a second point charge of -0.35 microC by a distance of 4.0 x10-4 m. Calculate the size of the force that each charge exerts on the other and its direction. (Assume 1/4 pi ε0 = 9.0 x109 m F-1)


Homework Equations



F = 1/(4 pi ε0) x (q1 x q2 / r-squared)


The Attempt at a Solution



I get an answer of -3.9 x 10 (power of 4) N

The question asks for the direction. So by stating the -'ve before the 3.9 am I indicating the direction?

Or should I state the answer is +3.9 x 10 (power of 4) N in a particular direction?

Thank you
 
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You've got the size of the force down. As for the direction: you have opposite charges, which means they attract one another. So your first answer (the negative one) is the one you should use.
 
Ok, thanks very much for the help Cryxic. It's very much appreciated. :smile:
 

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