- #1

- 321

- 20

## Homework Statement

[itex] {(x,y) ∈ ℝ^2 : (y-x)(y+x) = 0 } [/itex]

## Homework Equations

## The Attempt at a Solution

[/B]

Is the reason the answer is the union of y = -x and y = x because if you devide (y-x)(y+x) = 0 by y-x you get y = -x and if you devide (y-x)(y+x) = 0 by y+x you get y = x?

and if you multiply (y-x)(y+x) = 0 by any constant, after you devide by the factors you will get the same solutions anyways?