Sketch the graph of the wave-function.

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The discussion focuses on sketching the wave-function of a particle in its ground state based on a given potential graph. The user seeks validation of their sketch and asks for corrections to ensure their understanding before proceeding with further questions. Feedback indicates that the peak of the curve should be adjusted slightly, and the rightmost section of the wave-function should curve upwards instead of continuing downward. The conversation emphasizes the importance of accurately representing the wave-function to avoid fundamental errors in subsequent calculations. Accurate depiction of the wave-function is crucial for correct measurement predictions of the particle's location.
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Homework Statement



I am given the graph of the potential of a particle, and the particle is in its ground state. I must make the graph of the wave-function with respect to x.

(A) Sketch psi(x) for this particle.
(B) You make a measurement to find the particle. Indicate on your graph the point or points at which you are most likely to find it.


Homework Equations



Schrodinger's Time Independent equation with the second partial derivative with respect to x of the wave-function on the left-hand side and the Hamiltonian Operator on the right hand side.

The Attempt at a Solution



In the attached image. I just want to know if anything is incorrect, or if I am missing something, so that I don't do the rest of the questions fundamentally incorrectly. Thank you!
 

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That looks almost right to me. :smile:

Expect for one thing, you might want to move the peak of the curve indicated by point B just a touch.

The rightmost section of the wavefunction (right of the rightmost dashed, vertical line) should be curving upwards. But the way you've drawn it, some of the downward curvature from the previous section (The section containing B) looks to have crept over the dashed line.
 
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Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

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