Slope of position vs time squared graph?

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SUMMARY

The slope of a position vs. time squared graph, represented by the equation X = mt² + b, does not correspond to velocity or acceleration. Instead, it reflects the instantaneous speed at a given point on the curve, derived from the tangent line to the graph. The discussion emphasizes the importance of unit analysis to ensure dimensional consistency in physics equations, particularly when interpreting variables like distance and time.

PREREQUISITES
  • Understanding of quadratic functions and their graphical representations
  • Familiarity with basic physics concepts, specifically motion and kinematics
  • Knowledge of unit analysis in physics
  • Ability to interpret slopes of graphs in mathematical contexts
NEXT STEPS
  • Study the relationship between position, velocity, and acceleration in kinematics
  • Learn about the graphical interpretation of quadratic equations
  • Explore unit analysis techniques in physics for dimensional consistency
  • Investigate the concept of tangent lines and their slopes in calculus
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Students studying physics, particularly those focusing on kinematics and graph interpretation, as well as educators seeking to clarify concepts related to motion and graph analysis.

Tim Wellens
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Homework Statement


What would the slope of a position vs time squared graph represent?

Homework Equations


X=my^2+b

The Attempt at a Solution


I thought the slope of this graph would be velocity due to the fact that the normal position vs time graph slopes are velocity. However, I was told that the slope isn't velocity or acceleration. I'm not sure if it's correct or not?
 
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Your problem is in thinking that such a graph has a "slope". Strictly speaking "slope" is only defined for linear equations. If you mean "x= mt^2+ b" where t is time, measured in, say, seconds, while s is measured in meters, then the slope, not of the graph, but of the tangent line to the graph then we are approximating the quadratic function by a linear function, with x a distance and t time, then the slope of the tangent line is the speed at that instant.

(I notice that you have used "y" instead of the standard "t" for time so it is possible that y refers to something other than time. If that is true, what does "y" represent?)
 
Why don't you start with unit analysis? For each of the known quantities in the formula plug in a unit that would be associated with it. For example, if X is a distance, plug in the unit "meter". Then since for all physics equations the units must balance, determine what units the "m" in the formula must have in order for things to balance.
 

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