Small sample test concerning 2 means with different variances

  • Thread starter Thread starter toothpaste666
  • Start date Start date
  • Tags Tags
    Means Test
Click For Summary
SUMMARY

The forum discussion focuses on conducting a hypothesis test to compare the tensile strength of linen specimens subjected to a fusion process versus those that were not. Using a significance level of α = 0.05 and assuming unequal variances, the calculated t' value of -1.8 leads to the rejection of the null hypothesis (H0: μ1 - μ2 = 0) since it is less than the critical value of -1.746. The conclusion drawn is that the data supports the assertion that the fusion process increases tensile strength. Concerns regarding the normality of the population distributions were raised but deemed acceptable for this analysis.

PREREQUISITES
  • Understanding of hypothesis testing and null/alternative hypotheses
  • Familiarity with t-tests for small samples with unequal variances
  • Knowledge of calculating degrees of freedom for t-tests
  • Basic statistics concepts, including mean, standard deviation, and significance levels
NEXT STEPS
  • Study the application of the Welch's t-test for comparing means with unequal variances
  • Learn about the assumptions of normality in hypothesis testing
  • Explore the implications of sample size on statistical power and hypothesis testing
  • Review the use of software tools like R or Python for conducting t-tests and statistical analysis
USEFUL FOR

This discussion is beneficial for statisticians, data analysts, and researchers involved in hypothesis testing, particularly those working with small sample sizes and unequal variances in their data analysis.

toothpaste666
Messages
516
Reaction score
20

Homework Statement


The deterioration of many municipal pipeline networks across the county is a growing concern. An article stated that the fusion process increased the average tensile strength. Data on tensile strength (psi) of linen specimens when a certain fusion process was used and when this process was not given are provided. The data are given below.

Tensile strength (psi)
Nofusion 2748 2700 2655 2822 2511 3149 3257 3123 3220 2753
Fused 3027 3356 3359 3297 3125 2910 2889 2902

Carry out a test to see whether the data support this conclusion. Use α = 0.05. Assume
σ1 ≠ σ2

n1 = 10 x1 = 2902.8 s1 = 277.3 n2 = 8 x2 = 3108.1 s2 = 205.9

The Attempt at a Solution


μ1 = nonfusion μ2 = fused
H0: μ1 - μ2 = 0
H1: μ1 - μ2 < 0

for a small sample with unequal standard devations we use t'
reject H0 when t' < -tα = -t.05 for the estimated degrees of freedom v where

v = (s1^2/n1 + s2^2/n2)^2/[(s1^2/n1)^2/(n1-1) + (s2^2/n2)^2/(n2-1)]
= (277.3^2/10 + 205.9^2/8)^2/[(277.3^2/10)^2/9 + (205.9^2/8)^2/7]
= 15.9 ≅ 16

so reject H0 when t' < -1.746

t' = [(x1 - x2) - 0]/sqrt(s1^2/n1 + s2^2/n2) = (2902.8 - 3108.1)/sqrt(277.3^2/10 + 205.9^2/8)
= (-205.3)/113.97 = - 1.8
t' = -1.8 < -1.746
we must reject H0. the data supports the conclusion.

is this correct? I am slightly confused about if i should use t' or not because the problem never states that the populations are normal
 
Physics news on Phys.org
toothpaste666 said:
is this correct?
Seems OK to me (I am not a statistician, just a mathematician that has read up on basic statistics).
 
  • Like
Likes   Reactions: toothpaste666
Thank you. hopefully the assumption that the populations are normal doesn't cause me too much trouble
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 1 ·
Replies
1
Views
4K