SN2 Substitution Products: (2R, 3S)-3-methyl-2-methoxypentane

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Discussion Overview

The discussion revolves around the substitution products of the SN2 reaction involving (2S, 3S)-2-chloro-3-methylpentane and the nucleophile CH3O-. Participants explore the resulting stereochemistry and the nature of the product, debating whether it is an alcohol or an ether.

Discussion Character

  • Homework-related
  • Debate/contested
  • Exploratory

Main Points Raised

  • Some participants question whether the anti-attack of the nucleophile results in the inversion of configuration at both chiral centers or just at the one connected to the leaving group.
  • There is uncertainty regarding whether the product is an alcohol or an ether, with some participants asserting that the product should be an alcohol due to the presence of OH from the nucleophile's attack.
  • Others argue that the nucleophile CH3O- leads to the formation of an ether, as it can bridge two carbons after the leaving group Cl- departs, resulting in (2R, 3S)-3-methyl-2-methoxypentane.
  • Participants reference the Williamson ether synthesis in the context of forming an ether from the reaction.

Areas of Agreement / Disagreement

Participants do not reach a consensus on whether the product is an alcohol or an ether, with multiple competing views presented regarding the outcome of the reaction and the stereochemical implications.

Contextual Notes

There are unresolved questions about the stereochemical changes at the chiral centers and the specific nature of the product, which depend on the interpretation of the reaction mechanism and the role of the nucleophile.

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Homework Statement



Find the substitution products of ( 2S, 3S)-2-chloro-3-methylpentane + CH3O- in SN2 reaction.





The Attempt at a Solution



Will the anti-attack of the nucleophile result in the change of S to R for both the chiral carbons or just for the one with Cl connected to it? How can I know this?
 
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assaftolko said:

Homework Statement



Find the substitution products of ( 2S, 3S)-2-chloro-3-methylpentane + CH3O- in SN2 reaction.





The Attempt at a Solution



Will the anti-attack of the nucleophile result in the change of S to R for both the chiral carbons or just for the one with Cl connected to it? How can I know this?

The configuration of the carbon attached with Cl changes. The configuration changes only when the bonds to the chiral carbon break or change.
 
So I'll get (2R,3S)-3-methyl-2-pentanol?
 
assaftolko said:
So I'll get (2R,3S)-3-methyl-2-pentanol?

How do you get an alcohol? Shouldn't that be an ether?
 
How can it be ether? Cl is the leaving group and you get OH that is attached to the Cl's carbon from the other side. Now This carbon is directly attached to O, H, R and R', I don't see how the oxygen can be attached to 2 carbons to form ether...
 
assaftolko said:
How can it be ether? Cl is the leaving group and you get OH that is attached to the Cl's carbon from the other side. Now This carbon is directly attached to O, H, R and R', I don't see how the oxygen can be attached to 2 carbons to form ether...

Williamson ether synthesis.
 
assaftolko said:
How can it be ether? Cl is the leaving group and you get OH that is attached to the Cl's carbon from the other side. Now This carbon is directly attached to O, H, R and R', I don't see how the oxygen can be attached to 2 carbons to form ether...

You said in your first post that the nucleophile was CH3O-, not OH-. This would account for a carbon on one side of the oxygen. As this nucleophile attacks, it kicks away a Cl-, causing inversion of configuration and a new bond to carbon. That makes the oxygen bridge two carbons, forming an ether. I believe the correct answer would be (2R, 3S)-3-methyl-2-methoxypentane.
 
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