1. The problem statement, all variables and given/known data n-butyl alcohol was reacted with potassium bromide in the presence of concentrated sulphuric acid and water. 1) Is hydrobromic acid involved in this reaction? If yes, how so? 2) Is this reaction SN1 or SN2? What is the mechanism? 3) What is the purpose of the sulphuric acid and water? 2. Relevant equations - 3. The attempt at a solution 1) I believe HBr is involved, even though it's not added. Perhaps the bromide from potassium bromide and the hydrogen ion from sulphuric form HBr. 2) This is an SN2 reaction (substrate is a primary carbon). The hydroxyl group of the n-butyl alcohol undergoes protonation with HBr, while the nucleophilic Br- does a backside attack on the carbon atom which is attached to the alcohol group. The leaving group is the water molecule while n-butyl alcohol is converted into 1-bromobutane. 3) Sulphuric acid serves as a catalyst? Or to provide the hydrogen ions for protonation.. or for the formation of HBr? Quite confused over this question. Water seemingly serves as a solvent, but it's a protic solvent, which means that it will slow the reaction down. Why is this so? Any help would be greatly appreciated. Thanks in advance.