So I don't understand moon eclipses

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In summary, the classic moon diagram does not accurately depict the shadow of the moon during an eclipse. The shadow is significantly sharper when viewed from Earth than it is when depicted in a diagram.
  • #1
farolero
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here the classic moon diagram.

lunareclipse_zpsa114626f.gif

but the problem i see with this explanation is that in the penumbral shadow the center edge is 1% illuminated while the outer edge 99% illuminated

so if in the visible from Earth edge of the eclipse it goes form 0% illumination to 1% illumination why is it so noticeable, shouldn't it be more like a degradation?

we disccussed it in class to the question of a guy but we couldn get to an agreement so the teacher gave us an assignment on it

could someone help me here I am really lost on this one
 
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  • #2
Since you should be researching the topic - what have you done to find the answer on your own?

Some things to bear in mind: the picture is a very simple idealization - how often would the situation depicted happen?
is the picture to scale (does it matter)?
where do the numbers (1%, 99% etc) come from? Are they accurate?

Is the transition from the penumbra to the shadow a sharp one? How did you determine this?
 
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  • #3
well the first thing i did was checking if all moon eclipse diagram told the same story an they did:

https://www.google.es/search?q=moon...ved=0ahUKEwix3N2nnN_QAhVGWxQKHblyCKsQ_AUIBigB

so then i did a diagram rendering the issue discussed in class drawing a degradation:

Imagen0362_zpsdad84cac.jpg
so my view on the asignement will be that all those diagram are a simplification of the eclipse and actually Earth atmosphere plays a main role on it

the diagram i did is as it should be if there was no Earth's atmosphere

but Earth atmosphere acts as a lens and makes a sharp edge on the shadow of the eclipse as visible from Earth as i have witness myself

my teacher told us recently that the educative system was based in memorization so far but this makes no sense no more with the net so its being time to focus on creativity

so ill say that all those moon eclipse diagrams are a simplification and the problem they have is that is that simplification what explains the issue for without that simplification there wouldn't be an explanation from the jump step from grey to black

so ill take it as an example of the flaw of memorization in detriment of creativity, once the blindman steps on the stone all behind will follow

what I am working now on is to see if i can make an eclipse diagram which renders both the degradation of the penumbra an the sharpening lens effet of Earth's
atmosphere

the diagram of course is not to scale but we agree on class that being the angular size both of the sun and moon identical the size of the penumbra should be the same size than the moon

the situation depicted would happen every time there's a moon eclipse

the numbers 1% and 99% is a way to express the shadow should be an analogic degradation from black to white not a digital jump from black to grey to white

the shadow of the eclipse has been determined as sharp by several witnesses
 
  • #4
farolero said:
the shadow of the eclipse has been determined as sharp by several witnesses

It doesn't look that sharp in the following picture (and hundreds of others just like it I found on google images). It looks pretty "fuzzy" to me.

2014-04-17_534f1db352fe1_LunarEclipse4-15-2014.JPG
 
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  • #5
Your own diagram shows a Sun and Earth the same size: is this true in real life?
What difference does the real life scale make to the diagram - ie. Sun bigger but further away? (ie. what happens to the angular width of the penumbra?)
Your own diagram shows a sharp drop in sunlight at the edge between the penumbra and the umbra - could this not produce the sharp outline you saw?

Your sources are "several witnesses" and your own observation - so you would be relying on the human eye as an instrument to measure how the brightness changes across the face of the moon? How accurate is the eye at determining how sharp a brightness transition is?
How sharp is the transition between the part of the moon in the penumbra and the part in the umbra?
Perhaps finding photographs of total lunar eclipse online would be helpful rather than relying on your memory and stories from others? (See post #4 ... a lot depend on what you mean by "sharp".)
 
  • #6
in second and 6th moon it appears pretty sharp to me

anyway however distant by geometry the size of the penumbra of the eclipse is the same than the moon size, 0,5º of angular size
 
  • #7
farolero said:
in second and 6th moon it appears pretty sharp to me

Really? I definitely see a smooth dropoff in light intensity. Try looking for images in google. See if you can find one like the 2nd or 6th picture but much bigger so it's easier to see the shadow.
 
  • #8
farolero said:
in second and 6th moon it appears pretty sharp to me
What do you mean by "sharp"?

Your diagram - now I look more closely, appears to have a gradient from 0% to 99% across the penumbra
Can you verify that this information is correct? Could it be that the transition from say 50% to 99% happens in a relatively short space?
Can you find a more continuous brightness curve for the penumbral shadow?
 
  • #9
i think we are discussing the wrong thing

maybe we should discuss weather why not a single moon eclipse diagram paints a gradient or degradation from black to white but instead 3 drastic jumps from white to grey to white

i suppose you realize depending where youre on the moon in the penumbra you can see more or less of the sun
 
  • #10
yes my diagram tried to draw a graident but dint do it very well

here another try:
250312-0101.jpg
 
  • #11
I think I see your issue. It might be helpful to calculate the actual angles and linear diameter of the penumbra and the umbra: I think you will find that the penumbra is way, way oversized in that picture: smaller than the umbra.
 
  • #12
according geometry the size of the penumbra as seen from Earth has an angular size of 0.5 the same than the sun and moon

any sun shadow as seen from origin of the objet that causes the shadow has a penumbra of 0.5º angular size
 
  • #13
farolero said:
according geometry the size of the penumbra as seen from Earth has an angular size of 0.5 the same than the sun and moon
The Earth and sun are the two objects interacting to create the shadow, not the sun and moon...
 
  • #14
thats what i meant, accidentally sun and moon have the same angular size, 0.5º
 
  • #15
farolero said:
thats what i meant, accidentally sun and moon have the same angular size, 0.5º
We're talking about the shape of the shadows. The shadows are created by the Earth blocking the sun's light. So the umbra is the angular diameter of the Earth as seen from the moon and the penumbra is the additional angular diameter of the Sun as seen from the moon.

...but anyway, since we are most concerned about the penumbra and it is indeed half a degree, let's think about what that means:

To someone on the moon, they see a circular sun and a circular Earth that overlap during an eclipse. A person on one "edge" of the moon at the start of the eclipse for them will see the two cirlces just touching. Later, that person starts to see a total solar eclipse and at the same time a person on the other "edge" of the moon will see the eclipse just starting. Everyone else on the moon at that time will see a partially eclipsed (darkened) sun. And everyone on Earth at that time will see the moon nearly exactly in the penumbra and therefore partially, but unevenly darkened.

But how much? Well, because these are circles overlapping, they start slow and end quickly. In addition, our eyesight is not linear in terms of our ability to detect differences in brightness:
http://hyperphysics.phy-astr.gsu.edu/hbase/vision/bright.html

So when you see the first sliver of umbra getting cut out, the area around it is significantly darkened, but the area on the opposite side of the moon is still near full brightness. It isn't darkened enough for you to notice. Specifically, from the Hyperphysics link: a spot in the center of the moon at that time can still see well over half the sun, which makes it appear to Earth eyes somewhere around 80% of full brightness.
 
  • #16
The sharpness of the pictures has to do with the exposure. If you want to see some details in the umbra, you need to overexpose the penumbra, which gives its edge a sharper look.

Go outside on a sunny day and cast shadows with your hand. Notice that if your hand is close to the ground, you get sharp shadows. If you hold your hand above your head, it casts a fuzzy shadow on the ground.
 
  • #17
Here's a little more accurate representation of the Umbra and Penumbra shadows
umbra.jpg
 
  • #18
anyway the biggest concern about moon eclipses that we discussed in class was why nobody made an eclipse diagram with a degradation i the penumbra

the one kindly provided by janus is the first i see

is like for every 10000 diagrams just one makes a gradient

ill use this to back up the teacher point that so far people is been just memorizing stuff without thinking by themselves and as the first person who did the eclipse diagram made it without gradient all the rest copy him wrongly

also do you think the Earth atmosphere plays any role in sharpening the edge of the shadow or the photographs sharp edge have all overexposure?
 
  • #19
Janus said:
Here's a little more accurate representation of the Umbra and Penumbra shadows
View attachment 110003
That's cool, but isn't that a solar eclipse, not a lunar eclipse?
 
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  • #20
farolero said:
also do you think the Earth atmosphere plays any role in sharpening the edge of the shadow or the photographs sharp edge have all overexposure?

If anything I think the atmosphere does the opposite and blurs the edges more than they otherwise would be since it scatters lots of light.
 
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  • #21
farolero said:
also do you think the Earth atmosphere plays any role in sharpening the edge of the shadow or the photographs sharp edge have all overexposure?
"Overexposure" would mean parts of the photo are pure white, which wasn't the case. Nor do I think the atmosphere plays a role. I think it is all about the sensitivity of the eye and the steepness of the drop-off in light intensity due to the circular shapes overlapping.
 
  • #22
russ_watters said:
That's cool, but isn't that a solar eclipse, not a lunar eclipse?
Right, but it is a bit easier to see the Umbra/penumbra difference in that case.
Here's a Lunar eclipse. It is off scale in order to accent the fading off. ( the Earth/Moon size ratio is off, as is the Earth-Moon distance and Sun-Earth distance.)

umbra2.jpg

Different positions of the Moon are shown.

If I tried to do it to scale you can hardly see difference between umbra and penumbra
 
Last edited:

What causes a moon eclipse?

A moon eclipse occurs when the Earth passes between the Sun and the Moon, casting a shadow on the Moon's surface. This can only happen during a full moon phase, when the Earth, Sun, and Moon are aligned in a straight line.

How often do moon eclipses happen?

On average, there are two to four lunar eclipses every year. However, not all eclipses are visible from a specific location on Earth, as the Moon's orbit is tilted relative to the Earth's orbit around the Sun.

Why does the moon turn red during a lunar eclipse?

During a total lunar eclipse, the Moon appears to turn red because of a phenomenon called "Rayleigh scattering." This is when the Earth's atmosphere bends and filters sunlight, allowing the red wavelength to reach the Moon and giving it a reddish hue.

Can I look directly at a lunar eclipse?

Yes, it is safe to look directly at a lunar eclipse. Unlike a solar eclipse, it is not harmful to the eyes to look at the Moon during a lunar eclipse. In fact, it is recommended to observe this natural phenomenon without any special equipment.

How long does a lunar eclipse last?

The duration of a lunar eclipse varies, but on average it can last anywhere from 2 to 4 hours. The total phase of a lunar eclipse, when the Moon is fully covered by Earth's shadow, can last up to 1 hour and 45 minutes. However, the entire event, including the partial and penumbral phases, can last several hours.

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