How to Calculate Li+ Ion Concentration in Saturated Li3PO4 Solution?

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SUMMARY

The concentration of Li+ ions in a saturated Li3PO4 solution is calculated using the solubility product constant (Ksp) of 2.37 × 10-4. The correct concentration of Li+ ions is 0.0544 M, not 0.163 M as initially calculated. The discrepancy indicates a misunderstanding of the stoichiometry involved in the dissolution of Li3PO4, where each formula unit produces three Li+ ions. Thus, the concentration must be adjusted accordingly based on the Ksp value.

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  • Understanding of solubility product constants (Ksp)
  • Basic knowledge of stoichiometry in chemical reactions
  • Familiarity with lithium phosphate (Li3PO4) dissolution process
  • Ability to perform concentration calculations in saturated solutions
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Homework Statement


Lithium phosphate, Li3PO4, has a solubility product Ksp = 2.37 × 10-4. What is the concentration of Li+ ions in a saturated solution of Li3PO4?

The Attempt at a Solution



What is the initial concentration of Lithium? Or does it matter?

I got 0.163 M but answer says 0.0544 M

Without it I can't do it! Somebody please help. Thanks.
 
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0.163 M looks OK to me, 0.0544 is three times too low (which suggests an obvious mistake).
 
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Borek said:
0.163 M looks OK to me, 0.0544 is three times too low (which suggests an obvious mistake).

Ok thanks for confirming.
 

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