Solubility of an Acid: Separating Basic from Acid Compounds

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    Acid Solubility
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The unknown carboxylic acid is soluble in aqueous base because the strong base deprotonates the acid, forming a carboxylate ion that increases its solubility in water. In contrast, the acid remains mostly protonated and soluble in ether when mixed with an acid. To separate a basic compound from an acid compound, one can utilize the difference in solubility; the deprotonated salt formed in the base is soluble in water, while the weak acid remains soluble in ether. This method leverages the ionization of the acid in the presence of a strong base. Understanding these solubility principles is crucial for effective separation techniques.
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Homework Statement


I did an experiment where an extraction was done with an unknown carboxylic sample. Some mass of it was mixed with ether and aqueous NaOH then aqueous layer extracted, etc. The question asks though, why is the unknown compound soluble in aq. base not acid. Also, describe a process by which I would be able to separate a basic compound from an acid compound.

Homework Equations


The Attempt at a Solution



The only answer I can come up with is that there are more available proton acceptors in base allowing for the acid to be ionized and dissolve, but that answer seems too simple and I don't know if my logic is correct. And for the second question I have no idea.
 
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You're on the right track , the strong base deprotonates the acid therby increasing its solubility in water , if you know this then you should be able to answer the second question.
 
The salt (anionic carboxylate and the sodium cation) are not soluble in ether; they would be soluble in water. The caboxylic acid, weak acid and mostly protonated, is soluble in ether.
 

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